Question

我正在使用Oracle DB，并具有以下引发错误的查询：

ORA-00937：不是单组分组功能

查询：

select sum(ct.TOT_CT), ct.CREAT_TS, ev.EVENT
    from REF_CT ct
    inner join EVENT ev on ev.EVENT_TYPE_ID = ct.EVENT_TYPE_ID
    where ct.TX = 'SomeText';

如果我尝试单独访问以下内容，它将起作用。就像分别调用sum一样，分别是ct.CREAT_TS，依此类推。

问题似乎是在此查询中调用sum。我计划将输出捕获到对象（如果相关，则为Java）中。我希望查询输出如下。有可能做到这一点吗？

CREAT_TS                      EVENT          sum(ct.TOT_CT)
2019-04-02 01:33:46.227000    SOME_EVENT 1   8
2019-04-02 02:56:14.530000    SOME_EVENT 2

在给出答案之后，得到以下结果，其中总和值按列划分：

CREAT_TS                      EVENT          sum(ct.TOT_CT)
2019-04-02 01:33:46.227000    SOME_EVENT 1   2
2019-04-02 02:56:14.530000    SOME_EVENT 2   6

Answer 1

您需要包含group by子句。

select sum(ct.TOT_CT), ct.CREAT_TS, ev.EVENT
    from REF_CT ct
    inner join EVENT ev on ev.EVENT_TYPE_ID = ct.EVENT_TYPE_ID
    where ct.TX = 'SomeText'
    group by ct.CREAT_TS, ev.EVENT;

Answer 2

如果选择列表中至少存在一个聚合列，则需要按非聚合列进行分组

select sum(ct.TOT_CT), ct.CREAT_TS, ev.EVENT
    from REF_CT ct
    inner join EVENT ev on ev.EVENT_TYPE_ID = ct.EVENT_TYPE_ID
    where ct.TX = 'SomeText'
    group by ct.CREAT_TS, ev.EVENT

Answer 3

您可以使用窗口函数将总和放在每一行上：

your-command \
    | sort -V \
    | tail -n1 \
    | xargs basename

我不建议您仅将值放在一行上，但是您可以使用窗口函数来做到这一点：

select ev.EVENT, ct.CREAT_TS, sum(ct.TOT_CT), 
       sum(sum(ct.TOT_CT)) over ()
from REF_CT ct inner join
     EVENT ev
     on ev.EVENT_TYPE_ID = ct.EVENT_TYPE_ID
where ct.TX = 'SomeText'
group by ev.EVENT, ct.CREAT_TS;

如果您想要select ev.EVENT, ct.CREAT_TS, sum(ct.TOT_CT), (case when 1 = row_number() over (partition by ev.event order by ct.CREAT_TS) then sum(sum(ct.TOT_CT)) over () end) from REF_CT ct inner join EVENT ev on ev.EVENT_TYPE_ID = ct.EVENT_TYPE_ID where ct.TX = 'SomeText' group by ev.EVENT, ct.CREAT_TS order by ev.EVENT, ct.CREAT_TS;定义的第一行的总计，order by非常重要。

同一查询中的总和联接列数据

3 个答案: