Question

我有一个Laravel ORM查询，我将2-3关系连接在一起，如下所示：

$data = AccommodationRoom::with('accommodation.city',
    'accommodation.accommodationFacilities', 'accommodation.gallery')
    ->whereHas('roomCapacityHistory', function ($query) use ($from_date, $to_date) {
        $query->whereDate('from_date', '<=', $from_date);
        $query->whereDate('to_date', '>=', $to_date);
    })
    ->whereHas('accommodation', function ($query) use ($searchCity) {
        $query->where('city_id', $searchCity);
    })
    ->limit(10)->get();

return response()->json($data, 200);

在房间模型上，我检查容量模型是否有日期，以及城市ID是用户提供给酒店（住宿）的位置。问题是，当我得到结果时，每个房间都会得到重复的酒店。对于一次搜索，我可能会得到十家相同的酒店，因此我想使住宿变得唯一，并为每个住宿显示一个结果（房间）。

Answer 1

您可以使用groupBy而不是distinct；因为您要基于一个列对结果进行分组，例如，accommodation_id：

$data = AccommodationRoom::with('accommodation.city',
    'accommodation.accommodationFacilities', 'accommodation.gallery')
    ->SELECT('accommodation_id')
    ->whereHas('roomCapacityHistory', function ($query) use ($from_date, $to_date) {
        $query->whereDate('from_date', '<=', $from_date);
        $query->whereDate('to_date', '>=', $to_date);
    })
    ->whereHas('accommodation', function ($query) use ($searchCity) {
        $query->where('city_id', $searchCity);
    })
    ->groupBy('accommodation_id')->limit(10)->get();

return response()->json($data, 200);

Answer 2

尝试链接distinct method。

即：

$data = AccommodationRoom::with('accommodation.city',
    'accommodation.accommodationFacilities', 'accommodation.gallery')
    ->whereHas('roomCapacityHistory', function ($query) use ($from_date, $to_date) {
        $query->whereDate('from_date', '<=', $from_date);
        $query->whereDate('to_date', '>=', $to_date);
    })
    ->whereHas('accommodation', function ($query) use ($searchCity) {
        $query->where('city_id', $searchCity);
    })
    ->distinct('VALUE_FOR_HOTEL_HERE')->limit(10)->get();

return response()->json($data, 200);

如何在Laravel中的关系查询中使用区分

2 个答案: