Question

当我在RxJava中使用zip运算符来压缩2 Single时。 -我有Fixture对象和League对象，因为Api不会在Fixture中响应联盟的名称，所以我需要获取Fixture对象的id League，然后在League对象中进行查询。 -我的解决方案是我使用zip运算符来压缩治具和联赛的邮政编码，然后检查是否（治具中的LeagueId =联赛中的LeagueId）。最后，我设置了fixture.leagueName = League.name。但是问题是它的加载非常慢

 Single.zip(repository.getScoresFixtures(finalDate),
                leagueRepository.getAllLeagues(),
                BiFunction<FixtureResponse, LeagueResponse, List<Fixture>> { t1, t2 ->
                    return@BiFunction getNameFixtureLeague(t1, t2)
                })
                .subscribeOn(Schedulers.io())
                .observeOn(AndroidSchedulers.mainThread())
                .doOnSubscribe {
                    _scoreFixtureLiveData.value = ApiResponse.loading()
                }
                .subscribe({
                    _scoreFixtureLiveData.value = ApiResponse.success(it)
                }, {
                    _scoreFixtureLiveData.value = ApiResponse.error(it.message.toString())
                })

还有这个

private fun getNameFixtureLeague(
        fixtureResponse: FixtureResponse,
        leagueResponse: LeagueResponse
    ): List<Fixture> {
        val fixtures = fixtureResponse.data?.fixtures
        val leagues = leagueResponse.data?.leagues
        fixtures?.forEach {
            leagues?.first { league -> league.id == it.leagueId }.apply {
                it.leagueName = this?.name
            }
        }
        return fixtures!!
    }

我认为我的解决方案不好。有人可以帮我吗？

rxjava中的单个zip加载太慢

0 个答案: