Question

将数组与对象合并，并返回具有所有属性且对象值为null的数组

let object = {
  keys: {
    test1: {label: "Test_1"},
    test2: {label: "Test_2"},
    test3: {label: "Test_3"}
  }
}

let data = [{test1: "1", test2: "2", default:"123134" }, {test1: "1", test2: "2", default:"123134"}, {test1: "1", test3: "3"}, {test3: "3"}]

我期望下面的对象数组

let expectedArray = [{Test_1: "1", Test_2: "2", Test_3: null ,default:"123134" }, {Test_1: "1", Test_2: "2", Test_3: null,  default:"123134"}, {Test_1: "1", Test_3: "3", Test_2:null }, {Test_3: "3", Test_1: null, Test_2: null}]

在摘要下方尝试过

let res = data.map(o => {
  let obj = {}
  let c = Object.keys(o).forEach(aa => {
      obj[object.keys[aa].label] = o[aa]
  })
  return obj
})

任何帮助表示赞赏

Answer 1

您可以替换对象的现有键并重建新对象。

var object = { keys: { test1: { label: "Test 1" }, test2: { label: "Test 2" }, test3: { label: "Test 3" } } },
    data = [{ test1: "1", test2: "2", default: "123134" }, { test1: "1", test2: "2", default: "123134" }, { test1: "1", test3: "3" }, { test3: "3" }],
    templates = Object.values(object.keys).map(({ label }) => ({ [label]: null })),
    result = data.map(o => Object.assign(
        {},
        ...templates,
        ...Object
            .entries(o)
            .map(([k, v]) => ({ [k in object.keys ? object.keys[k].label : k]: v }))
    ));

console.log(result);

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用对象数组中的另一个属性替换键值

1 个答案: