我上下一节课:
A类用户:
@Entity
@JsonRootName(value = "user")
@Table(name = "web_users", schema = "t_dw_comercial")
public class User {
@Id
private int userId;
private String fullName;
private String ldapId;
private String email;
@ManyToOne
@JoinColumn(name= "u_type", nullable=false)
private Role uType;
private String deleteFlag;
private String typeAccess;
@OneToMany(fetch=FetchType.LAZY)
@JoinTable(name="web_users_roles",
joinColumns = {@JoinColumn(name="user_id")},
inverseJoinColumns = {@JoinColumn(name="role_id")}
)
private List<Role> roles;
}
A类角色:
@Entity
@JsonRootName(value = "roles")
@Table(name = "web_roles", schema = "t_dw_comercial")
public class Role {
@Id
private int roleId;
private String roleName;
@OneToMany
@JoinTable(name="web_users_roles",
joinColumns = {@JoinColumn(name="user_id")},
inverseJoinColumns = {@JoinColumn(name="role_id")})
private List<Section> sections = new ArrayList<Section>();
}
服务:
@Service
public class UserService implements IUserService{
@Autowired
UserRepository repository;
public User findUserByLdapId(String loginName) {
return repository.findUserByLdapId(loginName);
}
}
存储库:
@Repository
public interface UserRepository extends CrudRepository<User, Long>{
@Query("SELECT u FROM User u where u.ldapId= ?1")
public User findUserByLdapId(String loginName);
}
控制器:
@Controller
@RestController
public class UserController {
@Autowired
private IUserService userService;
@CrossOrigin
@RequestMapping(value = "/dashboard", params = {"user"}, method = RequestMethod.GET, produces = "application/json")
public ResponseEntity<User> getUser(@RequestParam(value = "user") String ldapId) {
User user = userService.findUserByLdapId(ldapId);
if(user == null)
return new ResponseEntity<>(HttpStatus.NO_CONTENT);
return new ResponseEntity<>(user, HttpStatus.OK);
};
}
如您所见,我在用户中有一个角色,并且有一个角色列表。称为uType的角色将类似于主要角色,而列表则是次要角色。我知道这个角色会出现两次,但是我一点也不在乎。
我想让主要角色渴望获得,而角色列表则可以根据需要懒惰获取,
所以json看起来像:
{
"user": {
"userId": 1,
"fullName": "Carolina Ponce",
"ldapId": "f8cygqn",
"email": "carolina@blabla.com",
"uType": {
"roleId": 1,
"roleName": "Admin",
"sections": [
{
"sectionId": 2,
"sectionName": "Admin",
"components": []
},
{
"sectionId": 1,
"sectionName": "Dashboard",
"components": [
{
"componentId": 2,
"componentName": "Provincia",
"jsonArray": [
{
"ID": "6",
"NAME": "BUENOS AIRES"
}
]
},
{
"componentId": 1,
"componentName": "Rubros",
"jsonArray": [
{
"ID": "1",
"NAME": "Automotriz"
},
{
"ID": "31",
"NAME": "Universidades"
}
]
}
]
}
]
},
"deleteFlag": "",
"typeAccess": ""
}
}
谢谢!
答案 0 :(得分:1)
我不确定我是否正确理解您的问题,因为Jpa / Hibernate默认情况下会这样做。默认情况下,所有* ToOne关系都是渴望的,而所有* ToMany关系都是默认懒惰的。
摘自@OneToMany
的文档。
public abstract FetchType fetch
(Optional) Whether the association should be lazily loaded or must be eagerly
fetched. The EAGER strategy is a requirement on the persistence provider runtime
that the associated entities must be eagerly fetched. The LAZY strategy is a
hint to the persistence provider runtime.
Default:
javax.persistence.FetchType.LAZY
并且来自@ManyToOne
public abstract FetchType fetch
(Optional) Whether the association should be lazily loaded or must be eagerly
fetched. The EAGER strategy is a requirement on the persistence provider runtime
that the associated entity must be eagerly fetched. The LAZY strategy is a hint
to the persistence provider runtime.
Default:
javax.persistence.FetchType.EAGER