Question

我想根据其他一些属性的值添加有条件的要求。仅当“ isInexperienced”时才需要“ companyName”和“ companyAddress” 值是假的。

架构

{
  "type": "object",
  "properties": {
    "previous_employment_section": {
      "type": "array",
      "items": {
        "type": "object",
        "properties": {
          "companyAddress": {
            "type": "string"
          },
          "companyName": {
            "type": "string"
          }
        },
        "if": {
          "#/properties/isInexperienced": {
            "const": false
          }
        },
        "then": {
          "required": [
            "companyName",
            "companyAddress"
          ]
        }
      }
    },
    "isInexperienced": {
      "type": "boolean"
    }
  }
}

数据

{
  "previous_employment_section": [],
  "isInexperienced": true
}

Answer 1

我不完全了解您的原始模式的意图，但是这个模式呢？

{
    "$schema": "http://json-schema.org/draft-07/schema#",
    "type": "object",
    "properties": {
        "previous_employment_section": {
            "type": "array",
            "items": {
                "type": "object",
                "properties": {
                    "companyAddress": {
                        "type": "string"
                    },
                    "companyName": {
                        "type": "string"
                    }
                }
            }
        },
        "isInexperienced": {
            "type": "boolean"
        }
    },
    "if": {
        "properties": {
            "isInexperienced": {
                "const": false
            }
        }
    },
    "then": {
        "properties": {
            "previous_employment_section": {
                "items": {
                    "required": [
                        "companyName",
                        "companyAddress"
                    ]
                },
                "minItems": 1
            }
        }
    }
}

Answer 2

不可能。我们需要更高级别的“如果”，则可以嵌套“属性”。可以使用Leadpony的方法。

JSON模式是否可以使用if / then / else引用外部属性

2 个答案: