Question

我试图显示表1包含的所有记录，每个记录以及表2中的所有记录：

Table 1

company  adress
------------------
 A        AdressX 
 B        AdressY
 C        AdressZ

Table 2

Product   Price
----------------
 P1        50 
 P2        60

Result :

company  Product
----------------
 A        P1 
 A        P2
 B        P1
 B        P2
 C        P1
 C        P2

Answer 1

那将是交叉联接。

SELECT t1.company,
       t2.product
       FROM [table 1] t1
            CROSS JOIN [table 2] t2
       ORDER BY t1.company,
                t2.product;

Answer 2

使用CROSS APPLY可以实现此预期输出：

SELECT T1.company, T2.Product
FROM Table1 T1
CROSS APPLY Table2  T2
ORDER BY T1.company, T2.Product

Demo on db<>fiddle

包含示例数据的演示

DECLARE @Table1 TABLE (company VARCHAR (1), adress VARCHAR (10));

INSERT INTO @Table1 (company, adress) VALUES
('A', 'AdressX'), 
('B', 'AdressY'),
('C', 'AdressZ');

DECLARE @Table2 TABLE (Product VARCHAR (2),   Price INT);

INSERT INTO @Table2 (Product, Price) VALUES
('P1', 50), 
('P2', 60);

SELECT T1.company, T2.Product
FROM @Table1 T1
CROSS APPLY @Table2  T2
ORDER BY T1.company, T2.Product

输出：

company Product
---------------
A       P1
A       P2
B       P1
B       P2
C       P1
C       P2

Answer 3

以下查询将从两个表中选择所有数据（未链接或相关）。

SELECT * 
FROM TABLE 1
OUTER APPLY
(
SELECT * 
FROM Table 2
) AS Table 2

如果有外键，则可以使用LEFT JOIN (SELECT)

如何从表2中的所有记录中选择表1

3 个答案: