Question

我从MySQL那里得到一份食物清单，我想基于相同的类别类型嵌套JSON输出。

我有一个用PHP编写的代码，我想转换为节点js。

function getAllFood($id){
    $stmt = $this->con->prepare("SELECT food.food_id, food.food_name, 
        food_category.food_category, food.food_price, food.res_branch_id, 
        food.food_type, food.food_desc, food.food_image FROM food, 
        food_category WHERE food.res_branch_id = ? AND food.food_category 
           = food_category.id");
    $stmt->bind_param("i",$id);
    $stmt->execute();
    $stmt->bind_result($food_id, $food_name, $food_category, $food_price, 
            $res_branch_id, $food_type, $food_desc, $food_image);

    $food = array();

    while($stmt->fetch()){
        $temp = array();
    $temp['food_id'] = $food_id;
    $temp['food_name'] = $food_name;
    $temp['food_category'] = $food_category;
    $temp['food_price'] = $food_price;
    $temp['res_branch_id'] = $res_branch_id;
    $temp['food_type'] = $food_type;
    $temp['food_desc'] = $food_desc;
    $temp['food_image'] = $food_image;

    array_push($food, $temp);
    }
    $data = [];

    foreach($food as $row){
            $category = $row['food_category'];
            if(!isset($data[$category])) {
                    $data[$category] = [
                    'title' => $category,
                    'section' => []
                    ];

        }
    $data[$category]['section'][] = ['id' => $row['food_id'], 'name' => $row['food_name'], 'image' => $row['food_image'], 'desc' => $row['food_desc'], 'price' => $row['food_price'], 'res_branch_id' => $row['res_branch_id'], 'food_type' => $row['food_type']];
    }
     return array_values($data);
}

 {
     "data": [
{
  "title": "Personal Pizza",
  "section": [
    {
      "id": 1,
      "name": "Tandoori Paneer",
      "image": "phut_0.jpg",
      "desc": "An all-indian fovourite made with paneer, tandoori marinade, onions and mozzarella cheese",
      "price": "60.83",
      "res_branch_id": 1,
      "food_type": "Veg"
    }
  ]
},
{
  "title": "Medium Pizza",
  "section": [
    {
      "id": 11,
      "name": "Tandoori Paneer",
      "image": "phut_0.jpg",
      "desc": "An all-Indian favourite made with paneer, tandoori marinade, onions and mozzarella cheese.",
      "price": "150",
      "res_branch_id": 1,
      "food_type": "Veg"
    }
  ]
},
{
  "title": "Large Pizza",
  "section": [
    {
      "id": 17,
      "name": "Giardino Feast",
      "image": "phut_0.jpg",
      "desc": "Go on a magical journey of veggies with jalapeno chillies, mushrooms, onions, corn baby corn and olives.",
      "price": "200",
      "res_branch_id": 1,
      "food_type": "Veg, New"
    }
  ]
}
  ]
 }

我想将下面的代码片段转换为node.js输出的MySQL。

 $data = [];

    foreach($food as $row){
            $category = $row['food_category'];
            if(!isset($data[$category])) {
                    $data[$category] = [
                    'title' => $category,
                    'section' => []
                    ];

        }
    $data[$category]['section'][] = ['id' => $row['food_id'], 'name' => $row['food_name'], 'image' => $row['food_image'], 'desc' => $row['food_desc'], 'price' => $row['food_price'], 'res_branch_id' => $row['res_branch_id'], 'food_type' => $row['food_type']];
    }

在Node.js下面的代码段中，我试图根据任务创建的日期来获取任务。请帮我转换以上逻辑。

router.get('/:user_id', checkAuth, (req,res,next) => {
const userId = req.params.user_id;

sql.query('SELECT * FROM task WHERE user_id = ?',[userId], (error, results, fields) => {
    if(error) {
        res.status(500).json({
            message: 'sql error'
        })
    } else {

       res.status(200).json({
           task: results
       })
    }
})
})

从节点js中的mysql输出更改json结构

0 个答案: