Question

这是我的路由器：

reportRoutes.route('/:id').get(async (req, res) => {
    try{
        let id = req.params.id
        console.log(req.query)
        let team = req.query.team
        let league_acronym = req.query.league
        console.log('team',team)
        let regex = new RegExp( id, 'i')
        const report = await Report.find({ title: regex })
            .populate({path: 'like'})
            .populate({
                path: 'player',
                populate: [{ path: 'team' },
                {
                    path: 'team',
                    populate: {
                        path: 'league'
                    }
                }
            ]
            })

            if(league_acronym) {
                newReport = report.filter((v,i) => {
                    return v.player.team.league.acronym === league_acronym  && v.player.team.team_name === team
                })
                res.json(newReport)
            } else{
                res.json(report)
            }
    }  catch (e) {
        res.status(500).send()
    }
})

我正在尝试设置一个通过报告并返回newReport的过滤器。

它将根据查询字符串参数进行过滤。

因为查询字符串参数将不会始终存在，所以我需要一种仅在条件存在时才对条件进行过滤的方法。有想法吗？

Answer 1

只有在league_acronym和team中有一个值，您才能检查相应的条件

newReport = report.filter(v => 
  (!league_acronym || v.player.team.league.acronym === league_acronym) 
  && (!team || v.player.team.team_name === team)
)

仅在变量条件未定义时过滤

1 个答案: