Question

我的问题是我正在列出联系人，电话号码显示的很好，但是我却无法使用姓名。

我尝试了几种获取“ DISPLAY_NAME”的方法，但没有一个起作用

    private void initializeRecyclerView() {
        mUserList = findViewById(R.id.userList);
        mUserList.setNestedScrollingEnabled(false);
        mUserList.setHasFixedSize(false);
        mUserListLayoutManager = new LinearLayoutManager(getApplicationContext(), LinearLayout.VERTICAL, false);
        mUserList.setLayoutManager(mUserListLayoutManager);
        mUserListAdapter = new UserListAdapter(userList);
        mUserList.setAdapter(mUserListAdapter);
        getContactsList();
    }

This is my adaptor ^^

    private void getContactsList(){
        Cursor phones = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, null, null, null);
        while(phones.moveToNext()){
            String phone = phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
            String name = phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));

            UserObject mContact = new UserObject(name, phone);
            userList.add(mContact);
            mUserListAdapter.notifyDataSetChanged();
        }
    }

Answer 1

我正在与此联系：-

private void getContactsList(){
        Cursor phones = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, null, null, null);
        while(phones.moveToNext()){
            String phone = phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
            String name = phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));
 UserObject mContact = new UserObject(name, phone);
            userList.add(mContact);
        }

 mUserListAdapter = new UserListAdapter(userList);
    mUserList.setAdapter(mUserListAdapter);
    }

，并设置获取联系人的权限：-

<uses-permission android:name="android.permission.READ_CONTACTS" />

Answer 2

您需要添加PROJECTION

您可以将此方法放入代码中

 public Cursor getContact(Context context) {
        String[] PROJECTION = new String[]{
                ContactsContract.RawContacts._ID,
                ContactsContract.Contacts.DISPLAY_NAME,
                ContactsContract.CommonDataKinds.Phone.NUMBER
               };
        Uri uri = CommonDataKinds.Phone.CONTENT_URI;

        String order = ContactsContract.Contacts.DISPLAY_NAME + " COLLATE LOCALIZED ASC";// LIMIT " + limit + " offset " + lastId + "";
        try {
            return context.getContentResolver().query(uri, PROJECTION, null, null, order);
        } catch (Exception e) {
            e.printStackTrace();
            return null;
        }
    }

并使用

获取名称

ContactsContract.Contacts.DISPLAY_NAME

快乐编码

取得联络人错误-如何解决？

2 个答案: