Question

我用数据库中的数据创建了该表。表格：https://imgur.com/06xnebJ

我需要将月份为May的所有行都放在1行中像这样：

2019年5月| | 3 | 3 | 2 | 等

我的数据库如下：

到目前为止，我已经获得了这段代码

$tipsportsql = mysqli_query($conn, "SELECT DATE_FORMAT(datum, '%b %Y') AS 'Monthyear', count(projekt) AS 'project' FROM zapasy WHERE projekt = '0' AND komentator1 = '$firstname $lastname' OR projekt = '0' AND komentator2 = '$firstname $lastname' GROUP BY Monthyear");

$slaviasql = mysqli_query($conn, "SELECT DATE_FORMAT(datum, '%b %Y') AS 'Monthyear', count(projekt) AS 'project' FROM zapasy WHERE projekt = '1' AND komentator1 = '$firstname $lastname' OR projekt = '1' AND komentator2 = '$firstname $lastname' GROUP BY Monthyear");

$betsql = mysqli_query($conn, "SELECT DATE_FORMAT(datum, '%b %Y') AS 'Monthyear', count(projekt) AS 'project' FROM zapasy WHERE projekt = '2' AND komentator1 = '$firstname $lastname' OR projekt = '2' AND komentator2 = '$firstname $lastname' GROUP BY Monthyear");

还有这个

<tbody>
        <?php while ($tip = mysqli_fetch_assoc($tipsportsql)) {?>
        <tr>
            <td>
                <?=$tip['Monthyear'] ?>
            </td>
            <td>

            </td>
            <td>

            </td>
            <td>
                <?=$tip['project']?>
            </td>
        </tr>

        <?php } while ($tip = mysqli_fetch_assoc($slaviasql)) {?>
        <tr>
            <td>
                <?=$tip['Monthyear'] ?>
            </td>
            <td>

            </td>
            <td>

            </td>
            <td>

            </td>
            <td>
                <?=$tip['project']?>
            </td>
        </tr>
        <?php }while ($tip = mysqli_fetch_assoc($betsql)) {?>
        <tr>
            <td>
                <?=$tip['Monthyear'] ?>
            </td>
            <td>

            </td>
            <td>
            <?=$tip['project']?>
            </td>
            <td>

            </td>
            <td>

            </td>
        </tr>
        <?php }?>
    </tbody>

感谢您的帮助。

Answer 1

我相信您想要这样的查询：

SELECT DATE_FORMAT(datum, '%b %Y') AS Monthyear, 
       SUM(projekt = 0) AS project_1,
       SUM(projekt = 1) AS project_2,
       SUM(projekt = 2) AS project_3
FROM zapasy
WHERE CONCAT(?, ?) IN (komentator1, komentator2)
GROUP BY Monthyear;

特别注意参数占位符。您需要学习如何使用参数，这样您的查询才不会遭受意外的语法错误和SQL注入攻击。

如何连接多个查询

1 个答案: