Question

显示销售月份和该月的销售数量，按销售降序排列。

我已经使用了提取功能从日期中提取月份，但是它给出的是月份编号而不是月份的全名

select extract(month from sldate) as month, count(sid) as number_sale from sale 
 group by sldate  
order by sid desc

这是桌子

销售表

SALEID  SID SLDATE
1001    1   01-JAN-14
1002    5   02-JAN-14
1003    4   01-FEB-14
1004    1   01-MAR-14
1005    2   01-FEB-14
1006    1   01-JUN-15

预期结果

MONTH        NUMBER_SALE
February    2
January         2
March           1
June            1

Answer 1

SELECT TO_CHAR(SLDATE, 'Month') Month, COUNT(SALEID) NUMBER_SALE FROM Sale GROUP BY TO_CHAR(SLDATE, 'Month') ORDER BY NUMBER_SALE DESC

Answer 2

您需要将其与年份相结合，而不是仅提取月份，因为您不想将不同月份的同一月的销售额混合使用，因此请使用year_month然后使用{{3} }以获取月份的名称：

select 
  monthname(concat(extract(year_month from sldate), '01')) as month, 
  count(sid) as number_sale 
from sale 
group by month
order by number_sale desc

请参见monthname()。
结果：

| month    | number_sale |
| -------- | ----------- |
| February | 2           |
| January  | 2           |
| March    | 1           |
| June     | 1           |

Answer 3

select to_char(sldate,'Month') as Month,count(*) as number_sale from sale group by to_char(sldate,'Month') order by count(*) desc 这是更简单的解决方案

Answer 4

select to_char(sldate,'Month') as month,count(sid) as NUMBER_SALE from sale 
  group by to_char(sldate,'Month') 
order by NUMBER_SALE desc

Answer 5

检查以下查询

SELECT TO_CHAR(SLDATE,'Month')"MONTH", COUNT(SID) AS NUMBER_SALE
FROM SALE
GROUP BY TO_CHAR(SLDATE,'Month')
ORDER BY COUNT(SID) DESC

显示销售月份和该月完成的销售数量（按销售降序排列）

5 个答案: