是否有任何函数可以使用$ needle作为数组来完成array_search的等效操作?比如,这将是一个理想的解决方案:
$needle = array('first', 'second');
$haystack = array('fifth','second','third', 'first');
// Returns key 1 in haystack
$search = array_search( $needle, $haystack );
如果没有函数,接受可能是我可用于创建自定义函数的数组的针的任何其他函数?
答案 0 :(得分:3)
这可能有助于建立你的功能:
$intersection = array_intersect($needle, $haystack);
if ($intersection) // $haystack has at least one of $needle
if (count($intersection) == count($needle)) // $haystack has every needle
答案 1 :(得分:2)
您可以使用array_intersect():http://php.net/manual/en/function.array-intersect.php
if (empty(array_intersect($needle, $haystack)) {
//nothing from needle exists in haystack
}
答案 2 :(得分:1)
$needle = array('first', 'second');
$haystack = array('fifth','second','third', 'first');
// Returns key 1 in haystack
function array_needle_array_search($needle, $haystack)
{
$results = array();
foreach($needle as $n)
{
$p = array_search($n, $haystack);
if($p)
$results[] = $p;
}
return ($results)?$results:false;
}
print_r(array_needle_array_search($needle, $haystack));
答案 3 :(得分:0)
$needle = array('first', 'second');
$haystack = array('fifth','second','third', 'first');
if(in_array($needle, $haystack)) {
echo "found";
}