Select
m.style_id,
sum(p.production_qty) Cutting
From
Master_Data m
Left Join
production_data p on P.Style_ID = M.Style_ID
where
p.production_process = 'Cutting',
sum(p.production_qty) Induction
From
Master_Data m
Left Join
production_data p on P.Style_ID = M.Style_ID
where
p.production_process = 'Induction',
group by
m.style_id
如何获得两个不同的select语句的结果?
答案 0 :(得分:2)
您可以使用条件聚合来获得所需的结果:
Select
m.style_id,
sum(case when p.production_process = 'Cutting' then p.production_qty else 0 end) Cutting
sum(case when p.production_process = 'Induction' then p.production_qty else 0 end) Induction
From
Master_Data m
Left Join
production_data p on P.Style_ID = M.Style_ID
where
p.production_process in ('Induction', 'Cutting')
group by
m.style_id
答案 1 :(得分:0)
根据您希望结果集的外观,可以使用聚合:
Select p.production_process, m.style_id,
sum(p.production_qty) Cutting
From Master_Data m left join
production_data p
on p.Style_ID = m.Style_ID and
p.production_process in ('Cutting', 'Induction')
group by p.production_process, m.style_id;