Question

我需要设置一些圆的半径，我有以下数据，由链接和节点组成。我需要将圆（节点）的半径设置为连接到节点的链接的总和

var data = {
    "nodes": [
        {
            "id": "s1",
            "val": 12
        },
        {
            "id": "s2",
            "val": 12
        },
        {
            "id": "s3",
            "val": 12
        },
        {
            "id": "s4",
            "val": 12
        },
        {
            "id": "s5",
            "val": 12
        },
        {
            "id": "s6",
            "val": 12
        }
    ],
    "Links": [
        {
            "n1": "s1",
            "n2": "s2",
            "amount": 10
        },
        {
            "n1": "s2",
            "n2": "s3",
            "amount": 10
        },
        {
            "n1": "s2",
            "n2": "s4",
            "amount": 10
        },
        {
            "n1": "s2",
            "n2": "s6",
            "amount": 10
        },
        {
            "n1": "s3",
            "n2": "s1",
            "amount": 10
        },
        {
            "n1": "s4",
            "n2": "s5",
            "amount": 10
        },
        {
            "n1": "s5",
            "n2": "s6",
            "amount": 10
        }
    ]
};

即（我希望节点此时处于上下文中），我在下面编写了一些伪代码

val1 = 0
val2 = 0 
for i to len.links
  if (links.node1 = nodes.id)
    val1 = val1 + links.amount
  else if (links.node02 = nodes.id)
    val2 = val2 + links.amount
next
sum = val1 + val2

下面的代码将圆圈显示在屏幕上，我尝试了各种方法，但是可以缓解我所说的死亡白屏

  var w = 1200;
  var h = 800;
  var svg = d3.select("body").append("svg").attr("width",w).attr("height", h);
      var lines = svg.attr("class", "line")
  d3.json("data.json", function(error, data) {
        console.log(data);

        var circles = svg.selectAll("foo")
  .data(data.nodes)
  .enter()
  .append("circle")
  .attr("cx", function(d) {
    return d.x;
  })
  .attr("cy", function(d) {
    return d.y;
  })
  .attr("r", 20); // <- i want to put this calculation here

我是JS新手，不知道如何将其转换为Javascript

Answer 1

由于d3可能会造成混淆，而js本身...还是很不错，我觉得这样花很长时间才能解释而不输入它。我在jsbin中一起破解了这个，并添加了一些注释。您应该能够逐行跟踪并找出发生了什么情况。如果您不了解或未发表评论，请使用Google语法，我会尽力帮助您进行推理。

jsbin并附有示例

const data = {
  "nodes": [
      {
          "id": "s1",
          "val": 12
      },
      {
          "id": "s2",
          "val": 12
      },
      {
          "id": "s3",
          "val": 12
      },
      {
          "id": "s4",
          "val": 12
      },
      {
          "id": "s5",
          "val": 12
      },
      {
          "id": "s6",
          "val": 12
      }
  ],
  "links": [
      {
          "n1": "s1",
          "n2": "s2",
          "amount": 10
      },
      {
          "n1": "s2",
          "n2": "s3",
          "amount": 10
      },
      {
          "n1": "s2",
          "n2": "s4",
          "amount": 10
      },
      {
          "n1": "s2",
          "n2": "s6",
          "amount": 10
      },
      {
          "n1": "s3",
          "n2": "s1",
          "amount": 10
      },
      {
          "n1": "s4",
          "n2": "s5",
          "amount": 10
      },
      {
          "n1": "s5",
          "n2": "s6",
          "amount": 10
      }
  ]
};


const width = window.innerWidth;
const height = window.innerHeight;
//set up the svg container
const svg = d3.select('body')
.append('svg')
.attr('width', width)
.attr('height', height)
.style('background-color', 'lightgray'); // just to see the outline

//update our data to have referable x, y positions for each node
data.nodes.forEach(n => { 
  n.x = Math.random()*width; //since I don't know how you want them arranged...
  n.y = Math.random()*height;//...i'm setting them randomly
})

//draw the lines
//each line has an x1,y1 and an x2,y2
//again not sure how you wanted them connected...
//so just doing the obvious based on the link info
const lines = svg.selectAll('line')
.data(data.links)
.enter()
.append('line')
.attr('stroke', 'black')
.attr('x1', l => {
  let node = data.nodes.filter(n => n.id === l.n1)[0];
  return node.x;
})
.attr('y1', l => {
  let node = data.nodes.filter(n => n.id === l.n1)[0];
  return node.y;
})
.attr('x2', l => {
  let node = data.nodes.filter(n => n.id === l.n2)[0];
  return node.x;
})
.attr('y2', l => {
  let node = data.nodes.filter(n => n.id === l.n2)[0];
  return node.y;
})
//draw the circles
const circles = svg.selectAll('circle')
.data(data.nodes)
.enter()
.append('circle')
// basically just random colors
.attr('fill', () => d3.color('#'+Math.floor(Math.random() * Math.pow(2,32) ^ 0xffffff).toString(16).substr(-6)))
.attr('cx', n => n.x)
.attr('cy', n => n.y)
.attr('r', n => {
  //for each node, first i find all the links that contain...
  //either n1 or n2 that matches the node's id
  let rels = data.links.filter(l => n.id === l.n1 || n.id === l.n2);
  //just google the reduce fn... it'll be easier...
  let sum = rels.reduce((a,b) => a + b.amount,0);
  return sum;
});
//add labels so we know whats what
const labels = svg.selectAll('text')
.data(data.nodes)
.enter()
.append('text')
.attr('x', n => n.x)
.attr('y', n => n.y)
.attr('text-anchor', 'middle') //horizontal align
.attr('alignment-baseline', 'central') //vertical align
.text(n => n.id)

尝试更新链接中的金额以查看动态更新/调整大小！

遍历JS中的JSON结构

1 个答案: