目前在列表，字符串和整数方面遇到麻烦

Question

我正在尝试通过编码纸牌游戏21的版本来挑战自己，但是我在字符串和整数方面遇到了麻烦。我的柜台也没有用，那超出了我

我尝试将所有内容定义为整数

定义

cardnum1 = " "
cardnum2 = " "

print("the dealer shuffles the cards and deals the first hand")
import random
list = ["2","3","4","5","6","7","8","9","10","Jack","Queen","King","Ace"]
#1st card
card1 = random.choice(list)
print("your first card is ",card1)
#numbers
if card1 == ["2","3","4","5","6","7","8","9","10"]:
    card1=int(cardnum1) 


elif card1 == "Jack":
    cardnum1=int(10)


elif card1 == "Queen":
    cardnum1=int(10)


elif card1 == "King":
    cardnum1=int(10)


elif card1 == "Ace":
    cardnum1=input("do you want your Ace to be a 1 or a 11?")




card2 = random.choice(list)
print("your second card is ",card2)

#numbers 1 - 10
if card2 == ["2","3","4","5","6","7","8","9","10"]:
    card1=int(cardnum1)

#special cards
elif card2 == "Jack":
    cardnum2=int(10)


elif card2 == "Queen":
    cardnum2=int(10)


elif card2 == "King":
    cardnum2=int(10)


elif card2 == "Ace":
    cardnum2=input("do you want your Ace to be a 1 or a 11?")


print ("your cards combined are ",cardnum1 + cardnum2)

我正尝试随机获得2张卡，并且让程序告诉我我距离21岁有多远，以及我是否破产。 cardnum1和cardnum2似乎没有正确添加。

我收到错误消息：

TypeError: can only concatenate str (not "int") to str

Answer 1

提到的错误是由于这样的事实，在某些情况下，这些变量之一是字符串，而另一个是整数。

实际上您有几处错误的事情：

1. list是python内置的，请勿将单词list用作变量。
2. if card1 == ["2","3","4","5","6","7","8","9","10"]是错误的。要检查变量是否在列表中，请执行：if card1 in ["2","3","4","5","6","7","8","9","10"]。请注意，in而不是==。
如果card1=int(cardnum1)是cardnum1，则
3. " "没有意义。您可能已将它们切换为：cardnum1 = int(card1)。
4. cardnum1=int(10)没错，但是10已经是一个整数。 int()是多余的，完全不需要。
5. cardnum2=input("do you want your Ace to be a 1 or a 11?")我想在这里您希望用户键入1或11。如果您使用的是python3，input总是返回一个字符串，因此必须将其转换为整数：{{1} }。如果您使用的是python2，就可以了。

Answer 2

您应该使用字典为卡片分配编号，并且可以使用from PyQt5 import QtCore, QtGui, QtWidgets, QtPrintSupport from PyQt5.QtGui import QIcon, QPixmap class Ui_MainWindow(object): def setupUi(self, MainWindow): MainWindow.resize(1920, 1080) self.Frame = QtWidgets.QWidget(MainWindow) self.Bild1 = QtWidgets.QLabel(self.Frame) self.Bild1.setGeometry(QtCore.QRect(20, 45, 600, 400)) pixmap1 = QPixmap('image1.JPG').scaled(600, 400) self.Bild1.setPixmap(pixmap1) self.Bild2 = QtWidgets.QLabel(self.Frame) self.Bild2.setGeometry(QtCore.QRect(660, 45, 600, 400)) pixmap2 = QPixmap('image2.JPG').scaled(600, 400) self.Bild2.setPixmap(pixmap2) self.Bild3 = QtWidgets.QLabel(self.Frame) self.Bild3.setGeometry(QtCore.QRect(1300, 45, 600, 400)) pixmap3 = QPixmap('image3.JPG').scaled(600, 400) self.Bild3.setPixmap(pixmap3) self.Bild4 = QtWidgets.QLabel(self.Frame) self.Bild4.setGeometry(QtCore.QRect(20, 565, 600, 400)) pixmap4 = QPixmap('image4.JPG').scaled(600, 400) self.Bild4.setPixmap(pixmap4) self.Bild5 = QtWidgets.QLabel(self.Frame) self.Bild5.setGeometry(QtCore.QRect(660, 565, 600, 400)) pixmap5 = QPixmap('image5.JPG').scaled(600, 400) self.Bild5.setPixmap(pixmap5) self.Bild6 = QtWidgets.QLabel(self.Frame) self.Bild6.setGeometry(QtCore.QRect(1300, 565, 600, 400)) pixmap6 = QPixmap('image6.JPG').scaled(600, 400) self.Bild6.setPixmap(pixmap6) self.WeiterButton = QtWidgets.QPushButton(self.Frame) self.WeiterButton.setGeometry(QtCore.QRect(1825, 1008, 75, 24)) MainWindow.setCentralWidget(self.Frame) self.WeiterButton.clicked.connect(self.print_widget) self.retranslateUi(MainWindow) QtCore.QMetaObject.connectSlotsByName(MainWindow) def retranslateUi(self, MainWindow): _translate = QtCore.QCoreApplication.translate MainWindow.setWindowTitle(_translate("MainWindow", "Fotobox")) self.WeiterButton.setText(_translate("MainWindow", "Print")) def print_widget(self): # Create printer printer = QtPrintSupport.QPrinter() # Create painter painter = QtGui.QPainter() # Start painter painter.begin(printer) # Grab a widget you want to print screen = self.Bild1.grab() # Draw grabbed pixmap painter.drawPixmap(0, 0, screen) # End painting painter.end() if __name__ == "__main__": import sys app = QtWidgets.QApplication(sys.argv) MainWindow = QtWidgets.QMainWindow() ui = Ui_MainWindow() ui.setupUi(MainWindow) MainWindow.show() sys.exit(app.exec_()) 选择2张卡片

random.choices

要轻松地将它们全部放入一个句子中，可以在Python 3.6+中使用import random cards = { 1: "Ace", 2: "2", 3: "3", 4: "4", 5: "5", 6: "6", 7: "7", 8: "8", 9: "9", 10: "10", 11: "Jack", 12: "Queen", 13: "King" } print("the dealer shuffles the cards and deals the first hand") card_num1, card_num2 = random.choices(list(cards), k=2) card1, card2 = cards[card_num1], cards[card_num2] print("your first card is ",card1) print("your second card is ",card2) 或f字符串。

.format()

Answer 3

正如我在评论中解释的那样，您错误地检查了列表包含，并且在if语句中设置了错误的变量。这是您的固定代码：

import random
cardnum1 = " "
cardnum2 = " "

print("the dealer shuffles the cards and deals the first hand")
list = ["2", "3", "4", "5", "6", "7", "8",
        "9", "10", "Jack", "Queen", "King", "Ace"]
# 1st card
card1 = random.choice(list)
print("your first card is ", card1)

# numbers
if card1 in ["2", "3", "4", "5", "6", "7", "8", "9", "10"]:
    cardnum1 = int(card1)


elif card1 == "Jack":
    cardnum1 = int(10)


elif card1 == "Queen":
    cardnum1 = int(10)


elif card1 == "King":
    cardnum1 = int(10)


elif card1 == "Ace":
    cardnum1 = input("do you want your Ace to be a 1 or a 11?")


card2 = random.choice(list)
print("your second card is ", card2)

# numbers 1 - 10
if card2 in ["2", "3", "4", "5", "6", "7", "8", "9", "10"]:
    cardnum2 = int(card2)

# special cards
elif card2 == "Jack":
    cardnum2 = int(10)


elif card2 == "Queen":
    cardnum2 = int(10)


elif card2 == "King":
    cardnum2 = int(10)


elif card2 == "Ace":
    cardnum2 = input("do you want your Ace to be a 1 or a 11?")

print("your cards combined are ", cardnum1 + cardnum2)

Answer 4

虽然其他人给出了您的程序的工作版本，并指出了您的版本存在的问题，但让我为您提供一个简单的选择：

import random

deck = ['Ace', 2, 3, 4, 5, 6, 7, 8, 9, 'Jack', 'Queen', 'King']

card1 = random.choice(deck)
card2 = random.choice(deck)

def card_value(card):
    if card == 'Ace':
        chosen_value = input("do you want your Ace to be a 1 or a 11?")
        return int(chosen_value)
    elif card in ['Jack', 'Queen', 'King']:
        return 10
    else:
        # Return the integer as it is
        return card

print("Your first card is", card1)
print("Your first card is", card2)

print("Your cards combined are ", card_value(card1) + card_value(card2))

此版本与您的版本之间唯一的主要区别是，我使用card_value帮助方法来将卡的值导出为整数。如果卡值已经是整数，则照原样返回。

PS：

欢迎来到编程世界，这很酷，您现在就尝试挑战自己。不必担心您的问题会否决票；它发生了。但是您可以通过有条不紊地解决您的问题来避免这种情况：

• 首先用纯英语或伪代码写下一个算法
• 编写代码并测试算法的每个阶段
• 编写测试以检查预期输出与实际输出

在一开始，您可能会发现，花时间并学习像程序员一样思考，比深入研究任何一种语言都更有益。查看这些链接以了解我的意思：

• https://zapier.com/blog/think-like-a-programmer/
• https://www.amazon.com/Think-Like-Programmer-Introduction-Creative/dp/1593274246
• https://medium.freecodecamp.org/how-to-think-like-a-programmer-lessons-in-problem-solving-d1d8bf1de7d2