Question

是否可以将Swagger 2内容移动到另一个基本URL？

我已经看到“ how to do friendly base url for swagger 2.8.0”以及这种解决方法：

@RequestMapping("/swagger")
public String greeting() {
    return "redirect:/swagger-ui.html";
}

问题：

在我看来，这是不可能的！

我的服务器托管两个Web应用程序和一个REST api，这就是为什么我在这里遇到这个怪物的原因：

@Controller
public class ForwardController {

    @RequestMapping(value = "/sitemap.xml", method = RequestMethod.GET)
    public String redirectSitemapXml(HttpServletRequest request) {
        return "forward:/a/web/assets/sitemap.xml";
    }

    @RequestMapping(value = "/robots.txt", method = RequestMethod.GET)
    public String redirectRobotTxt(HttpServletRequest request) {
        return "forward:/a/web/assets/robots.txt";
    }

    @RequestMapping(value = "/*", method = RequestMethod.GET)
    public String redirectRoot(HttpServletRequest request) {
        return "forward:/a/web/index.html";
    }

    @RequestMapping(value = "/a/**/{path:[^.]*}", method = RequestMethod.GET)
    public String redirectClients(HttpServletRequest request) {

        String requestURI = request.getRequestURI();

        if (requestURI.startsWith("/a/admin/")) {
            return "forward:/a/admin/index.html";
        }

        return "forward:/a/web/index.html";
    }

}

此设置与Spring Security设置一起使用。

我需要大摇大摆才能在/a/swagger-ui.html下工作，但这有可能吗？

在我的ForwardController下，以下各项均无法工作：

How to change Swagger-ui URL prefix?

Answer 1

您可以定义RouterFunction

@SpringBootApplication
public class MyApp {
public static void main(String[] args) {
    SpringApplication.run(MyApp.class, args);
}
@Bean
RouterFunction<ServerResponse> routerFunction() {
    return route(GET("/swagger"), req ->
        ServerResponse.temporaryRedirect(URI.create("swagger-ui.html")).build());
}
}

或创建一个WebFilter：

@Component
public class SwaggerWebFilter implements WebFilter {
    @Override
    public Mono<Void> filter(ServerWebExchange exchange, WebFilterChain chain) {
        ServerHttpRequest request = exchange.getRequest();
        String path = request.getPath().pathWithinApplication().value();
        if (path.startsWith("/api/swagger-ui.html") || path.startsWith("/api/webjars")
                || path.startsWith("/api/api-docs") || path.startsWith("/api/configuration")
                || path.startsWith("/api/swagger-resources") || path.startsWith("/api/v2"))) {
            exchange = exchange.mutate().request(request.mutate().path(path.substring(4)).build()).build();
        }
        return chain.filter(exchange);
    }
}

设置swagger.ui.html的基本路径

1 个答案: