在一种方法中找不到但在另一种方法中找到的TypeORM存储库

时间:2019-05-25 16:02:00

标签: node.js postgresql typeorm

我使用TypeORM连接到nodeJS中的postgresql数据库。我在以下地方遇到了这个奇怪的问题:

public static async organizationRelations(name){
    let connection = getConnection();

    const org = await connection.getRepository(Organization).find({
        where:[{name: name}]
    });
    return org;
}

可以,但是:

public static async importOrganizations(body){
    let connection = getConnection();
    let objs = {};


    let o = await connection.getRepository(Organization).save(this.createObjects(body, objs));

}

没有。

对于保存方法,我不断收到错误RepositoryNotFoundError: No repository for "Organization" was found. Looks like this entity is not registered in current "default" connection?

为什么它只能在一个功能中起作用,而不能在另一个功能中起作用?

2 个答案:

答案 0 :(得分:0)

您是否尝试删除此行?

<?xml version="1.0" encoding="UTF-8"?> 
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
    <modelVersion>4.0.0</modelVersion>
    <parent>
        <groupId>org.springframework.boot</groupId>
        <artifactId>spring-boot-starter-parent</artifactId>
        <version>2.1.5.RELEASE</version>
        <relativePath/> <!-- lookup parent from repository -->
    </parent>
    <groupId>com.example</groupId>
    <artifactId>SpringInAction</artifactId>
    <version>0.0.1-SNAPSHOT</version>
    <name>SpringInAction</name>
    <description>Demo project for Spring Boot</description>

    <properties>
        <java.version>1.8</java.version>
    </properties>

    <dependencies>
        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter</artifactId>
        </dependency>

        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-test</artifactId>
            <scope>test</scope>
        </dependency>
    </dependencies>

    <build>
        <plugins>
            <plugin>
                <groupId>org.springframework.boot</groupId>
                <artifactId>spring-boot-maven-plugin</artifactId>
            </plugin>
        </plugins>
    </build>

</project>

答案 1 :(得分:0)

我在mu App.ts中做到了这一点

private async databaseConnection(){
await createConnection(options).then(connection =>{
  this.express.emit("app_started");
});

}

问题是我正在使用chai测试,并且在应用完全初始化之前就开始了测试。