想知道如何将RECEIVEDDATETIME传递给以下语句。我的SQL语句中缺少什么？
由于Mark Barinstein，我向CALENDAR表和TESTDATA表添加了内部联接，以将T.RECEIVEDDATETIME作为原始示例的日期传递。
此语句从我的tblCalendar获取C.WORKDATE，但是我需要传递T.RECEIVEDDATETIME来获取所需的“ DUEDATE”。
我创建了一个“ tblCalendar”，因为我读到它可以更轻松地引用真实工作日的日历...以排除周末和节假日并解释leap年。不确定这是否是最佳实践，但似乎很直接地不为异常编写代码。因此，我创建了tblCalendar，其中包含从2017年到2050年及节假日的所有日期。下面的数据仅代表了2019年1月的部分数据，因为我还没有找到在此处附加表格的方法：
tblCalendar (partial)
DATE NUMDAYOFWK DAYOFWK HOLIDAY
01/01/2019 3 Tuesday YES
01/02/2019 4 Wednesday
01/03/2019 5 Thursday
01/04/2019 6 Friday
01/05/2019 7 Saturday
01/06/2019 1 Sunday
01/07/2019 2 Monday
01/08/2019 3 Tuesday
01/09/2019 4 Wednesday
01/10/2019 5 Thursday
01/11/2019 6 Friday
01/12/2019 7 Saturday
01/13/2019 1 Sunday
01/14/2019 2 Monday
01/15/2019 3 Tuesday
01/16/2019 4 Wednesday
01/17/2019 5 Thursday
01/18/2019 6 Friday
01/19/2019 7 Saturday
01/20/2019 1 Sunday
01/21/2019 2 Monday YES
tblTestData表包含核心数据，我在其中引用了报告所需的所有字段。
tblTestData Columns (partial) - DeliveryDays would reference the 2nd parameter BusDayAdd that was noted in the previous SQL.
ID RECEIVEDDATE DeliveryDays Address
T-20190116-255 01/16/2019 2 1234 Address
T-20190117-255 01/17/2019 2 3657 Address
T-20190118-222 01/18/2019 2 9999 Address
T-20190119-255 01/19/2019 2
T-20190120-255 01/20/2019
T-20190121-255 01/21/2019
T-20190303-1 03/03/2019
考虑到我的tblTestData中的RECEIVEDDATETIME并参考tblCalendar表以排除周末和节假日以给出正确的到期日，所需的最终结果如下所示。
ID RECEIVEDDATE DeliveryDays DueDate Address
T-20190116-255 1/16/2019 2 1/18/2019 1234 Address
T-20190117-255 1/17/2019 2 1/22/2019 3657 Address
T-20190118-222 1/18/2019 2 1/23/2019 9999 Address
T-20190119-255 1/19/2019 2 1/23/2019 10000 Address
T-20190120-255 1/20/2019 2 1/23/2019 10001 Address
T-20190121-255 1/21/2019 2 1/23/2019 10002 Address
T-20190121-256 1/22/2019 2 1/24/2019 10003 Address
T-20190303-1 3/3/2019 3 3/6/2019 10004 Address
T-20190121-257 3/15/2019 7 3/26/2019 10005 Address
我通过重写代码以包装SQL字符串以传递表“ RECEIVEDDATETIME”来尝试各种语句，但是每次“ DUEDATE”返回{NULL}时。
SELECT T.ID, VARCHAR_format(T.RECEIVEDDATETIME, 'MM/DD/YYYY') RECDATE,
(select VARCHAR_FORMAT(WORKDATE,'MM/DD/YYYY') DUEDATE
from
(Select
WORKDATE, T.RECEIVEDDATETIME,
sum(case when C.HOLIDAY='YES' or C.NUMDAYOFWK in (7,1) then 0 else 1 end) over (order by C.WORKDATE) BUSDAYADD
from tblCALENDAR C
--ADDED INNER JOIN TO GET T.RECEIVEDDATETIME TO FEED AUTOMATICALLY FROM TESTDATA TABLE
INNER JOIN TESTDATA T
ON
VARCHAR_FORMAT(C.WORKDATE, 'MM/DD/YYYY') = VARCHAR_FORMAT(T.RECEIVEDDATETIME,'MM/DD/YYYY')
where C.WORKDATE > VARCHAR_FORMAT(T.RECEIVEDDATETIME,'MM/DD/YYYY')) -- 1-st PARAMETER TO CAPTURE RECEIVEDDATETIME
WHERE BUSDAYADD = ? -- 2-nd parameter to add the number of days needed to be added to RECEIVEDDATETIME
order by WORKDATE --3rd Parameter
fetch first 1 row only)
FROM TESTDATA T
WHERE ID = 'T-20190303-1'
运行SQL时，DUEDATE的结果为{NULL}：
ID RECDATE DUEDATE
T-20190303-1 03/03/2019 {NULL}
结果应为：
ID RECDATE DUEDATE
T-20190303-1 03/03/2019 03/05/2019
感谢您的帮助。
答案 0 :(得分：0)
DUEDATE的SELECT是
INNER JOIN TESTDATA T
ON VARCHAR_FORMAT(C.WORKDATE, 'MM/DD/YYYY') = VARCHAR_FORMAT(T.RECEIVEDDATETIME,'MM/DD/YYYY')
where C.WORKDATE > VARCHAR_FORMAT(T.RECEIVEDDATETIME,'MM/DD/YYYY'))
这意味着您加入平等，然后限制为工作日期> Receiveddatetime 可能是问题所在...
答案 1 :(得分：0)
您在两个表中提供的数据不一致：tblTestData表中除第一个记录外的所有记录的日历都为时过早。
让我提供绝对相同的查询，我之前已经将其发送给您另一个问题。
with tblCalendar (DATE, HOLIDAY) as (values
(date(to_date('01/16/2019', 'MM/DD/YYYY')), '')
, (date(to_date('01/17/2019', 'MM/DD/YYYY')), '')
, (date(to_date('01/18/2019', 'MM/DD/YYYY')), '')
, (date(to_date('01/19/2019', 'MM/DD/YYYY')), '')
, (date(to_date('01/20/2019', 'MM/DD/YYYY')), '')
, (date(to_date('01/21/2019', 'MM/DD/YYYY')), 'YES')
, (date(to_date('01/22/2019', 'MM/DD/YYYY')), '')
, (date(to_date('01/23/2019', 'MM/DD/YYYY')), '')
, (date(to_date('01/24/2019', 'MM/DD/YYYY')), '')
, (date(to_date('01/25/2019', 'MM/DD/YYYY')), '')
, (date(to_date('01/26/2019', 'MM/DD/YYYY')), '')
, (date(to_date('01/27/2019', 'MM/DD/YYYY')), '')
, (date(to_date('01/28/2019', 'MM/DD/YYYY')), '')
, (date(to_date('01/29/2019', 'MM/DD/YYYY')), '')
, (date(to_date('01/30/2019', 'MM/DD/YYYY')), '')
, (date(to_date('01/31/2019', 'MM/DD/YYYY')), '')
, (date(to_date('02/01/2019', 'MM/DD/YYYY')), '')
, (date(to_date('02/02/2019', 'MM/DD/YYYY')), '')
, (date(to_date('02/03/2019', 'MM/DD/YYYY')), '')
, (date(to_date('02/04/2019', 'MM/DD/YYYY')), '')
, (date(to_date('02/05/2019', 'MM/DD/YYYY')), '')
)
, tblTestData (ID, RECEIVEDDATE, DeliveryDays) as (values
('T-20190116-255', date(to_date('01/16/2019', 'MM/DD/YYYY')), 2)
, ('T-20190117-255', date(to_date('01/17/2019', 'MM/DD/YYYY')), 2)
, ('T-20190118-222', date(to_date('01/18/2019', 'MM/DD/YYYY')), 2)
, ('T-20190119-255', date(to_date('01/19/2019', 'MM/DD/YYYY')), 2)
, ('T-20190120-255', date(to_date('01/20/2019', 'MM/DD/YYYY')), 2)
, ('T-20190121-255', date(to_date('01/21/2019', 'MM/DD/YYYY')), 2)
, ('T-20190121-256', date(to_date('01/22/2019', 'MM/DD/YYYY')), 2)
, ('T-20190303-1' , date(to_date('01/23/2019', 'MM/DD/YYYY')), 3)
, ('T-20190121-257', date(to_date('01/24/2019', 'MM/DD/YYYY')), 7)
)
select m.*, t.date as DUEDATE
--, dayofweek(date) as DAYOFWK, dayname(date) as DAY
from tblTestData m
, table
(
select date
from table
(
select
date
, sum(case when HOLIDAY='YES' or dayofweek(date) in (7,1) then 0 else 1 end) over (order by date) as dn_
from tblCalendar t
where t.date > m.RECEIVEDDATE
)
where dn_ = m.DeliveryDays
fetch first 1 row only
) t;
结果是：
ID RECEIVEDDATE DAYS DUEDATE
-------------- ------------ ---- ----------
T-20190116-255 2019-01-16 2 2019-01-18
T-20190117-255 2019-01-17 2 2019-01-22
T-20190118-222 2019-01-18 2 2019-01-23
T-20190119-255 2019-01-19 2 2019-01-23
T-20190120-255 2019-01-20 2 2019-01-23
T-20190121-255 2019-01-21 2 2019-01-23
T-20190121-256 2019-01-22 2 2019-01-24
T-20190303-1 2019-01-23 3 2019-01-28
T-20190121-257 2019-01-24 7 2019-02-04