我有一个包含项目列表的页面。页面底部是“查看更多”按钮。当有人单击此按钮时,页面需要添加更多项目。 var是$ displayedquestions,当点击“查看更多”按钮时,页面现在被编码以刷新,但是我们希望它能够实时显示。怎么办呢?
这是代码:
<?php
include "db_connect.php";
db_connect();
function tags($tags)
{
$tagarray=explode(",",$tags);
$i=0;
$finished='false';
while($finished=='false') {
if (empty($tagarray[$i])=='true') {
$finished='true';
} else {
$taglist = $taglist . '<a class="commonTagNames" href="">' . $tagarray[$i] . '</a> ';
$i++;
}
}
return $taglist;
}
function formattime($timesince)
{
$strsince=number_format($timesince,0,'','');
$nodecimals=intval($strsince);
if ($nodecimals<1){
return "Less than a minute ago";
} elseif ($nodecimals>=1&&$nodecimals<60) {
return $nodecimals . " min ago";
} elseif ($nodecimals>60&&$nodecimals<1440){
$hourssince=$nodecimals/60;
$hoursnodecimals=number_format($hourssince,0);
return $hoursnodecimals . " hours ago";
} elseif ($nodecimals>1440){
$dayssince=$nodecimals/1440;
$daysnodecimals=number_format($dayssince,0);
return $daysnodecimals . " days ago";
}
}
$submitbutton=$_REQUEST['viewmore'];
$numquestions=intval($_REQUEST['questions']);
if($numquestions!=0) {
$displayedquestions=$numquestions;
} else {
$displayedquestions=10;
}
$sql="SELECT * FROM `Questions` ORDER BY `Questions`.`ID` DESC LIMIT 0, " . $displayedquestions;
$questions=mysql_query($sql);
while($row = mysql_fetch_array($questions))
{
$id = $row['ID'];
$user = $row['userAsking'];
$question = $row['question'];
$tags = $row['tags'];
$timestamp = $row['timestamp'];
$time=strtotime($timestamp);
$secondssince=(date(U)-$time)/60;
$timesince=formattime($secondssince);
$responses=mysql_query("SELECT * FROM `answersToQuestions` WHERE `idOfQuestion`= '$id'");
$comments=mysql_num_rows($responses);
$likes=mysql_query("SELECT * FROM `likesOfQuestions` WHERE `idOfQuestion`= '$id'");
$numlikes=mysql_num_rows($likes);
$userprofileq = mysql_query("SELECT `ID`,`avatar` FROM `Users` WHERE `username` = '$user'");
$userprofileresult = mysql_fetch_row($userprofileq);
$linktoprofile = $userprofileresult[0];
$avatar = $userprofileresult[1];
$taglist=tags($tags);
echo "</li>";
echo '<li class="questionsList" onclick="showUser(' . $id . ')">
<div id="questionPadding">
<img class="askerImage" width=50 height=50 src="../Images/userimages/' . $avatar . '.png"/>
<div class="questionFirstRow"><h1 class="questionTitle">' . $question . '</h1></div>
<span class="midRow">
<span class="askerSpan"><a class="askerName" href="">'. $user .'</a></span>
</span>
<span class="bottomRow">
<img src="../Images/comment.png"/>
<span class="comments">' . $comments . '</span>
<img src="../Images/likes.png"/>
<span class="likes">' . $numlikes . '</span>
' . $timesince . '
</span>
</div>
</li>';
}
?>
<center><a href="index.php?questions=<?php echo $displayedquestions+10; ?>"><img class="moreQuestions" src="../Images/viewMoreBar.png" alt="More" /></a></center>
答案 0 :(得分:2)
如果没有做很多工作,你可以添加ajax。使用此功能:
首先,(我假设您将上面的代码包含在另一个文件中)围绕它创建一个容器。例如:
<div id='container'>...</div>
其次,将此javascript添加到包含您上面代码的页面:
<script type="text/javascript">
$(function(){
$("#container img.moreQuestions").parent().live('click', (function (e) {
e.preventDefault();
$("#container").load($(this).attr("href"));
});
});
});
</script>
这将加载到您已经拥有的脚本#container
,而不刷新页面的其余部分。
注意我示例中More
链接(斜杠按钮)的选择器为$("#container img.moreQuestions").parent()
,因为您没有类或ID。您应该为More
链接指定一个类或ID,并将其用于选择器。
答案 1 :(得分:0)