Question

=IF(M13>9,IF(P13="","", IF(K13="V", ($A$4+(INDEX('Minimum Visual Inspection Times'!$A$2:$P$15, MATCH(C13,'Minimum Visual Inspection Times'!$A$1:$A$15,TRUE), MATCH(D13,'Minimum Visual Inspection Times'!$A$2:$P$2,))))/(60*60*24), (($A$3+$A$2*2)+(INDEX('Minimum M21 Screening Times'!$A$2:$P$17, MATCH(C13,'Minimum M21 Screening Times'!$A$2:$A$17,TRUE), MATCH(D13,'Minimum M21 Screening Times'!$A$2:$P$2,))))/(60*60*24))),IF(P13="","", IF(K13="V", ($A$4+(INDEX('Minimum Visual Inspection Times'!$A$2:$P$15, MATCH(C13,'Minimum Visual Inspection Times'!$A$1:$A$15,TRUE), MATCH(D13,'Minimum Visual Inspection Times'!$A$2:$P$2,))))/(60*60*24), (($A$3)+(INDEX('Minimum M21 Screening Times'!$A$2:$P$17, MATCH(C13,'Minimum M21 Screening Times'!$A$2:$A$17,TRUE), MATCH(D13,'Minimum M21 Screening Times'!$A$2:$P$2,))))/(60*60*24))))

我已经编写了以上代码，但代码未提供确切结果。任何人都可以帮助我解决问题。 sql查询生成如下：

Criteria criteria = createEntityCriteria().addOrder(Order.asc("dtname"));
ProjectionList projection = Projections.projectionList();
projection.add(Projections.distinct(Projections.property("dtncode")));
projection.add(Projections.property("dtname"));
criteria.setProjection(projection);
List<VillageMaster> villageMasters = (List<VillageMaster>) 
criteria.list();

Answer 1

使用以下代码

Criteria criteria = createEntityCriteria().addOrder(Order.asc("dtname"));    
ProjectionList projection = Projections.projectionList();
projection.add(Projections.property("dtncode"));
projection.add(Projections.property("dtname"));
criteria.setProjection(Projections.distinct(projection));
List<VillageMaster> villageMasters = (List<VillageMaster>) 
criteria.list();

Hibernate Criteria查询无法提供完整的结果

1 个答案: