我想做一个可变的动作,根据那些选定图层之一的最宽宽度来分隔一系列图层。 4个精灵分别为100、100、100、200像素宽。它在x轴上将所有图层分开200像素,使图像的总宽度为800像素。
如果所有层都相同,我就能轻松地做到这一点,但不能使其具有可变性。不知道是否有任何photoshop向导愿意花我时间来制作脚本,但这会非常有帮助!
答案 0 :(得分:1)
我会做这样的事情。这假定没有组,没有背景层,各层是普通层,并且所有文档层都已使用。前后(最大150px):
如果不需要它们更改Y
的位置,请在第13行将0 - layersInfo[i].top
更改为0
。
function main()
{
var doc = activeDocument,
layers = doc.layers, //getting all top layers
layersInfo = getInfo().reverse(), //getting layers info and reversing the array because DOM indexes are different order than AM indexes
elWidth = getWidestElement(layersInfo); // getting widest element
doc.resizeCanvas(elWidth * layers.length, doc.height.as("px"), AnchorPosition.TOPLEFT); // resizing canvas size to new width: widest element * number of elements
for (var i = 0; i < layers.length; i++) // for every top layer...
{
doc.activeLayer = layers[i]; // selecting the layer
layers[i].translate(i * elWidth - layersInfo[i].left, 0 - layersInfo[i].top) // moving it to top left corner of each block
}
function getInfo()
{
var layers = 1,
lyrs = [];
while (true)
{
ref = new ActionReference();
ref.putIndex(charIDToTypeID('Lyr '), layers);
try
{
var desc = executeActionGet(ref);
}
catch (err)
{
break;
}
var lyr = {},
bounds = desc.getObjectValue(stringIDToTypeID("bounds"));;
lyr.top = bounds.getDouble(stringIDToTypeID("top"));
lyr.left = bounds.getDouble(stringIDToTypeID("left"));
lyr.width = bounds.getDouble(stringIDToTypeID("width"));
lyrs.push(lyr)
layers++;
}
return lyrs
}; // end of getInfo()
function getWidestElement(layers)
{
var curWidth = 0;
for (var i = 0; i < layers.length; i++)
{
if (layers[i].width > curWidth) curWidth = layers[i].width;
}
return curWidth
}; // end of getWidestElement()
}
var curUnits = app.preferences.rulerUnits;
app.preferences.rulerUnits = Units.PIXELS;
try
{
app.activeDocument.suspendHistory("temp", "main()");
}
catch (e)
{
alert(e + '\nLine: ' + e.line)
}
app.preferences.rulerUnits = curUnits;