Question

我一直在尝试从数据库中提取州，城市和计数列表，并将其显示如下。点击更多按钮将扩展每个州的其他城市。不幸的是，所有州及其城市和计数都在同一显示列中，我无法将州彼此分开。我似乎无法将各州及其特定城市分成不同的列。任何帮助将不胜感激。

Alaska(46)
Anchorage(22)
Eagle River(2)
Elmendorf Afb(1)
Fairbanks(7)
Juneau(4)
More...

点击更多链接后：

Alaska(46)
Anchorage(22)
Eagle River(2)
Elmendorf Afb(1)
Fairbanks(7)
Juneau(4)
Ketchikan(1)
Kodiak(1)
Alabama(54) <-- next state loaded in output, I want this separate
Auburn(1)
Bessemer(1)
Birmingham(52)
Less...

这是我的查询：

  $query = "
    SELECT 
      stateAbv,
      stateName,
      '' AS cityName,
      count(*) AS state_count 
    from
      my_data 
    GROUP BY stateAbv, stateName 
    union
    SELECT 
      stateAbv,
      stateName,
      city AS cityName,
      COUNT(*) AS city_count 
    FROM
      my_data 
    GROUP BY stateAbv, stateName,
      city 
    ORDER BY stateAbv,
      cityName asc
  ";
  $sqlResult = mysqli_query($con, $query);


 $i = 0;


 while ($row = mysqli_fetch_array($sqlResult)) {
    if ($i++ == 6) break;
    if ($row['cityName']) {
        echo $row['cityName'] . "(" . $row['state_count'] . ")" . "<br/>";
    } else {
        echo $row['stateName'] . "(" . $row['state_count'] . ")" . "<br/>";
    }
 }
 echo "<a class='more-detail' style='cursor: pointer; font-color:#0000ff;'>More...</a>";

 echo "<div class='detail-section' style='display: none;'>";
  while ($row = mysqli_fetch_array($sqlResult)) {
    if ($i++ > 6) {
        if ($row['cityName']) {
            echo $row['cityName'] . "(" . $row['state_count'] . ")" . "<br/>";
        } else {
            echo $row['stateName'] . "(" . $row['state_count'] . ")" . "<br/>";
        }
    }

 }
 echo "<a class='less-detail' style='cursor: pointer; font-color:#0000ff;'>Less...</a>";
 echo "</div>";

?>

这是我的js，用于展开/折叠列表：

<script>
$(document).ready(function(){

  $(".more-detail").click(function(){
    $(".detail-section").css("display", "block");
    $(".more-detail").css("display", "none");
  });

  $(".less-detail").click(function(){
    $(".detail-section").css("display", "none");
    $(".more-detail").css("display", "block");
  });

});
</script>

Answer 1

此方法的问题在于mysqli_fetch_array已经在第一个循环中获取了结果。要做的简单事情就是做类似的事情：

  $query = "
    SELECT 
      stateAbv,
      stateName,
      '' AS cityName,
      count(*) AS state_count 
    from
      my_data 
    GROUP BY stateAbv, stateName 
    union
    SELECT 
      stateAbv,
      stateName,
      city AS cityName,
      COUNT(*) AS city_count 
    FROM
      my_data 
    GROUP BY stateAbv, stateName,
      city 
    ORDER BY stateAbv,
      cityName asc
  ";
  $sqlResult = mysqli_query($con, $query);


 $i = 0;


 while ($row = mysqli_fetch_array($sqlResult)) {

    if ($row['cityName']) {
        echo $row['cityName'] . "(" . $row['state_count'] . ")" . "<br/>";
    } else {
        echo $row['stateName'] . "(" . $row['state_count'] . ")" . "<br/>";
    }

    if ($i == 6){
     echo "<a class='more-detail' style='cursor: pointer; font-color:#0000ff;'>More...</a>";

     echo "<div class='detail-section' style='display: none;'>";
     }
    $i++;
 }

 echo "<a class='less-detail' style='cursor: pointer; font-color:#0000ff;'>Less...</a>";
 echo "</div>";

?>

Answer 2

$query = "
    SELECT
          stateAbv
        , stateName
        , city AS cityName
        , COUNT(city) As city_count
        , COUNT(stateName) As state_count
    FROM
        my_data
    GROUP BY
          stateName
        , city
    ORDER BY
          stateName
        , city      
";
$sqlResult = mysqli_query($con, $query);
while ($row = mysqli_fetch_array($sqlResult)) {
    $state_name = "{$row['stateName']} ({$row['state_count']})"
    $city_name = "{$row['cityName']} ({$row['city_count']})"
    $cities[$state_name][{$row['cityName']}] = $city_name;
}

foreach ( $cities As $state ) {
    echo "<p>State: $state </p>";
    foreach ( $state As $city ) {
        echo "$city<br />";
    }
    echo '<br />';
}

?>

这些都没有经过测试，我没有任何示例数据可以对其进行测试，并且无法单击以显示和隐藏细节。它要做的是根据查询结果创建一个多维数组。您可以使用javascript在单击状态时扩展状态的详细信息（认为该技术被称为手风琴）

Mysqli_fetch_array

2 个答案: