Question

我需要从c#代码执行shell命令，然后将shell的输出记录到文件中。

我用来执行shell命令的代码是：

using (var process = Process.Start(new ProcessStartInfo
{
    FileName = fileName,
    Arguments = arguments,
    CreateNoWindow = false,
    WindowStyle = ProcessWindowStyle.Normal,
    RedirectStandardOutput = false,
    UseShellExecute = true,
}))
{
    // blocking wait for the process to end
    process.WaitForExit();
}

我阅读了其他更改RedirectStandardOutput = true和useShellExecute = false的答案，以便他们可以通过获取控制台输出

string output = process.StandardOutput.ReadToEnd();

但这不会打开外壳窗口。

是否可以将命令输出显示到控制台窗口并获取该输出？

Answer 1

可以使用类似的东西

using System;
using System.Diagnostics;

    namespace InteractWithConsoleApp
    {
        class Program
        {
            static void Main(string[] args)
            {
                ProcessStartInfo cmdStartInfo = new ProcessStartInfo();
                cmdStartInfo.FileName = @"C:\Windows\System32\cmd.exe";
                cmdStartInfo.RedirectStandardOutput = true;
                cmdStartInfo.RedirectStandardError = true;
                cmdStartInfo.RedirectStandardInput = true;
                cmdStartInfo.UseShellExecute = false;
                cmdStartInfo.CreateNoWindow = true;

                Process cmdProcess = new Process();
                cmdProcess.StartInfo = cmdStartInfo;
                cmdProcess.ErrorDataReceived += cmd_Error;
                cmdProcess.OutputDataReceived += cmd_DataReceived;
                cmdProcess.EnableRaisingEvents = true;
                cmdProcess.Start();
                cmdProcess.BeginOutputReadLine();
                cmdProcess.BeginErrorReadLine();

                cmdProcess.StandardInput.WriteLine("ping google.com.ua");     //Execute ping google.com.ua
                cmdProcess.StandardInput.WriteLine("exit");                  //Execute exit.

                cmdProcess.WaitForExit();
            }

            static void cmd_DataReceived(object sender, DataReceivedEventArgs e)
            {
                Console.WriteLine("Output from other process");
                Console.WriteLine(e.Data);
            }

            static void cmd_Error(object sender, DataReceivedEventArgs e)
            {
                Console.WriteLine("Error from other process");
                Console.WriteLine(e.Data);
            }
        }
    }

将进程的输出重定向到文件和控制台

1 个答案: