在Android Studio中将新记录插入sqlite的问题

Question

我想在sqlite数据库中插入一条新记录。 我的表称为class MyPageControl: UIPageControl { override func sendAction(_ action: Selector, to target: Any?, for event: UIEvent?) { super.sendAction(action, to: target, for: event) updateSomething(for: currentPage) } } 。它具有列words，id，word，meaning，details，lesson列。

当我尝试插入新记录时，它只是将ticks保存为details，而将word保存为lesson，而meaning和{{1} }以空值存储。 自动增量主键details和lesson正确存储。

---

代码

处理程序：

id

对象：

ticks

OnClickListener：

public class DatabaseHandler extends SQLiteOpenHelper {

private static final int DATABASE_VERSION = 1;
protected static final String DATABASE_NAME = "wordDatabase";

public DatabaseHandler(Context context) {
    super(context, DATABASE_NAME, null, DATABASE_VERSION);
}

@Override
public void onCreate(SQLiteDatabase db) {

    String sql = "CREATE TABLE words " +
            "( id INTEGER PRIMARY KEY AUTOINCREMENT, " +
            "word TEXT, " +
            "meaning TEXT, " +
            "details TEXT, " +
            "lesson TEXT, " +
            "ticks INTEGER ) ";
    db.execSQL(sql);

}

@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {

    String sql = "DROP TABLE IF EXISTS words";
    db.execSQL(sql);
    onCreate(db);
}

在 public class ObjectStudent { int id; String word; String meaning; String details; String lesson; int ticks; public ObjectStudent(){ } 类上创建方法：

public class OnClickeListenerCreateStudent implements View.OnClickListener {
@Override
public void onClick(View view) {
    final Context context = view.getRootView().getContext();

    LayoutInflater inflater = (LayoutInflater) context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
    final View formElementsView = inflater.inflate(R.layout.student_input_form, null, false);

    final EditText et_word = (EditText) formElementsView.findViewById(R.id.et_word);
    final EditText et_meaning = (EditText) formElementsView.findViewById(R.id.et_meaning);
    final EditText et_details = (EditText) formElementsView.findViewById(R.id.et_details);
    final EditText et_lesson = (EditText) formElementsView.findViewById(R.id.et_lesson);


    new AlertDialog.Builder(context)
            .setView(formElementsView)
            .setTitle("Create Word")
            .setPositiveButton("Add",
                    new DialogInterface.OnClickListener() {
                        public void onClick(DialogInterface dialog, int id) {
                            String wordTitle = et_word.getText().toString();
                            String wordMeaning = et_meaning.getText().toString();
                            String wordDetails = et_details.getText().toString();
                            String wordLesson = et_lesson.getText().toString();

                            ObjectStudent objectStudent = new ObjectStudent();
                          /*  objectStudent.word= wordTitle;
                            objectStudent.meaning= wordMeaning;
                            objectStudent.details= wordDetails;
                            objectStudent.lesson= wordLesson;*/
                            objectStudent.word = "word"; // et_word.getText().toString();
                            objectStudent.meaning = "meaning"; // et_meaning.getText().toString();
                            objectStudent.details = "details"; // et_details.getText().toString();
                            objectStudent.lesson = "lesson"; // et_lesson.getText().toString();

                            objectStudent.ticks= 1;

                            boolean createSuccessful = new TableControllerStudent(context).create(objectStudent);

                            if(createSuccessful){
                                Toast.makeText(context, "Word information was saved.", Toast.LENGTH_SHORT).show();
                            }else{
                                Toast.makeText(context, "Unable to save Word information.", Toast.LENGTH_SHORT).show();
                            }

                            ((MainActivity) context).countRecords();
                            ((MainActivity) context).readRecords();



                            dialog.cancel();
                        }

                    }).show();
}

Answer 1

只需将数据库版本更新为更高版本（而不是1，请使用5）。并检查它。在运行应用程序之前，请先卸载然后再运行。

Answer 2

使用

db.insert(YOUR_TABLE_NAME,values);

代替

db.execSQL()功能