Question

有一个值列表：

list_inside = ["de:14612:1","de:14612:21","de:14612:17","de:14612:16"]

为什么我得到这个{'from': '1', 'to': '16'}而不是{'from': '16', 'to': '16'}。我的代码在做什么错了？

keys = ["from", "to"]

list_inside = ["de:14612:1","de:14612:21","de:14612:17","de:14612:16"]

for i in list_inside[::len(list_inside)-1]:
    result = dict((key, i.join(i.split(":", 2)[2::1])) for key in keys)

print(result)

Answer 1

使用

(C|M)?

输出：

[CM]?

您当前的方法是覆盖keys = ["from", "to"] list_inside = ["de:14612:1","de:14612:21","de:14612:17","de:14612:16"] result = {} #Declare empty dict for key, v in zip(keys, list_inside[::len(list_inside)-1]): result.update({key: v.split(":", 2)[-1])}) #Use dict.update to update the required values. print(result)变量。

Answer 2

您在一个循环中多次result =。

很明显，这里只有最后一次迭代才有效。

Answer 3

此代码将获得预期的结果。 -1编写了简单的代码。

keys = ["from", "to"]

list_inside = ["de:14612:1","de:14612:21","de:14612:17","de:14612:16"]

result = {}
result[keys[0]] = list_inside[0].split(':')[2]
result[keys[1]] = list_inside[-1].split(':')[2]

print (result)

使用Python将列表转换成字典

3 个答案: