使用PHP获取今天一周的日期

时间:2011-04-11 23:29:08

标签: php

如何从今天起一周后以下列格式获取日期:YYYY-MM-DD?

感谢。

5 个答案:

答案 0 :(得分:90)

尝试:

date("Y-m-d", strtotime("+1 week"));

这将输出:

2015-12-31

如果今天是2015-12-24

答案 1 :(得分:18)

正如Charles的预测错误,这是一个PHP 5.3+示例:

$now = new DateTime;
$interval = new DateInterval('P1W')
$next_week = $now->add($interval);
echo $next_week->format('Y-m-d');

或稍微紧凑的形式:

$now = new DateTime();
echo $now->add(new DateInterval('P1W'))->format('Y-m-d');

答案 2 :(得分:7)

<?php
$nextWeek = time() + (7 * 24 * 60 * 60);
echo 'Next Week: '. date('Y-m-d', $nextWeek) ."\n";

查尔斯预测遗失了一个人,straight from the horses mouth, example #1

答案 3 :(得分:7)

将天,周,月添加到任何日期

 $date = date("Y-m-d");// current date

 $date = strtotime(date("Y-m-d", strtotime($date)) . " +1 day");

 $date = strtotime(date("Y-m-d", strtotime($date)) . " +1 week");

 $date = strtotime(date("Y-m-d", strtotime($date)) . " +2 week");

 $date = strtotime(date("Y-m-d", strtotime($date)) . " +1 month");

 $date = strtotime(date("Y-m-d", strtotime($date)) . " +30 days");

答案 4 :(得分:1)

    for ($i=0 ; $i < 7 ;$i++)
    {
        $date[]=date('Y-m-d',strtotime("+{$i} day",time()));
    }

    print_r($date);