Question

我具有在Django中创建新用户的功能，如下所示：

def initialize(username, password, email, title, firstName, lastName,  telephoneNumber, mobileNumber, smsActive, for_company_id = 1):
    sUsername = username.lower()
    if len(username) > 30:
        sUsername = username[:30].lower()
    user = User.objects.create_user(sUsername, email, password, last_login=datetime.datetime.now())
    user.first_name = firstName
    user.last_name = lastName
    user.save()
    userProfile = UserProfile(user = user, title = title, telephone = telephoneNumber, mobile = mobileNumber, smsActive = smsActive)
    userProfile.code2Factor = pyotp.random_base32()
    userProfile.forCompanyId = for_company_id
    userProfile.main_updated = datetime.datetime.now()
    userProfile.save()
    return userProfile

然后我按如下操作：

user_profile = initialize(input.user.username, password, '', input.title, input.user.first_name, input.user.last_name, input.telephone, input.mobile, sms_active)
user_profile.user.groups.set([Group.objects.get(id=gr.id) for gr in input.groups])
user_profile.cultureMajor = input.cultureMajor
user_profile.offerTax = input.offerTax if 'offerTax' in input else False
user_profile.user.save()

但是当我尝试创建新用户时，出现如下错误：

duplicate key value violates unique constraint "auth_user_pkey" DETAIL: Key (id)=(21811) already exists.

ID 21811存在于数据库中，但最后一个是25530。

为什么django不使用ID的第一个下一个号码？

更新

用户模型是django的标准模型。

UserProfile如下：

class UserProfile(models.Model):
    forCompanyId = 1
    user = models.OneToOneField(to=User, on_delete=models.DO_NOTHING)
    title = models.CharField(max_length=10, null=True, blank=True)
    telephone = models.CharField(max_length=50, null=True, blank=True)
    mobile = models.CharField(max_length=50, null=True, blank=True)
    smsActive = models.BooleanField(default=False)
    car_by_car_notification = models.BooleanField(default=True)
    car_by_car_mail = models.BooleanField(default=True)
    daily_digest = models.BooleanField(default=True)
    offer_tax = models.BooleanField(default=False)
    cultureMajor = models.CharField(max_length=3, blank=False, default='en')
    cultureMinor = models.CharField(max_length=3, blank=True)
    modulesBlocked = models.ManyToManyField(to=Module, through='UserModuleBlocked')
    otherEmails = models.CharField(max_length=512, null=True, blank=True)
    otherContact = models.CharField(max_length=256, null=True, blank=True)
    browser = models.CharField(max_length=256, null=True, blank=True)
    picture = models.ImageField(upload_to=settings.MEDIA_ROOT, blank=True, null=True)
    code2Factor = models.CharField(max_length=256, null=True, blank=True)
    mobile2Factor = models.BooleanField(default=False)
    authenticator2Factor = models.BooleanField(default=False)
    main_user_id = models.IntegerField(null=True)
    main_updated = models.DateTimeField(_('date updated on main'), default=timezone.now)

Answer 1

这不是Django的问题

duplicate key violates a unique constraint

创建重复密钥时，会出现此消息。在您的情况下，这可能意味着您正在使用的表中的主键序列已不同步。这可能是由于手动导入，对于我来说，遇到此问题时通常就是这种情况。您必须手动重置主键索引。

我不确定您的数据库是什么，我将与您共享用于修复该数据库的粗糙的Postgres SQL命令，前两个允许您查看它是否不同步，而后一个则可以修复它，如果所以。如果这还不够/它的数据库不同，请发表评论

SELECT MAX('auth_user_pkey') FROM User;   
SELECT nextval('auth_user_key_sequence');

SELECT setval('auth_user_key_sequence', (SELECT MAX(auth_user_pkey) FROM User)+1);

Answer 2

我通过执行以下代码解决了这个问题：

BEGIN;
SELECT setval(pg_get_serial_sequence('"auth_permission"','id'), coalesce(max("id"), 1), max("id") IS NOT null) FROM "auth_permission";
SELECT setval(pg_get_serial_sequence('"auth_group_permissions"','id'), coalesce(max("id"), 1), max("id") IS NOT null) FROM "auth_group_permissions";
SELECT setval(pg_get_serial_sequence('"auth_group"','id'), coalesce(max("id"), 1), max("id") IS NOT null) FROM "auth_group";
SELECT setval(pg_get_serial_sequence('"auth_user_groups"','id'), coalesce(max("id"), 1), max("id") IS NOT null) FROM "auth_user_groups";
SELECT setval(pg_get_serial_sequence('"auth_user_user_permissions"','id'), coalesce(max("id"), 1), max("id") IS NOT null) FROM "auth_user_user_permissions";
SELECT setval(pg_get_serial_sequence('"auth_user"','id'), coalesce(max("id"), 1), max("id") IS NOT null) FROM "auth_user";
COMMIT;

重复键值违反了Django中唯一的约束

2 个答案: