Question

我从URL抓取JSON对象并使用JSON.NET解析它。我能够用定义的变量解析数据块就好了，但是当涉及var：value的随机收集时 - 我被卡住了。

示例（松散输入）：

{"FNAME":"joe","LNAME":"doe", "BodyType":{"height":180,"weight":"200","race":"white","hair":"black"}, "BELONGINGS":{"shirt":"black","Money":15,"randomThing":"anyvar"}, "Signs":{"tattoo":0,"scar":"forehead","glasses":"dorky"} }

我正在将其转换为

Class Person { public string FNAME; public string LNAME; public BodyType bodyType; public ????? belongings; public ????? signs; } 如果我无法预测其属性，我该如何处理物品和标志？

Answer 1

有两种方法可以在不知道运行时的内容的情况下处理它们。

第一种方法是使用JSON.Net的JObject，它将处理您提到的案例以及层次结构。

第二种方法是使用System.Dynamic的ExpandoObject，这是最新版本的JSON.Net新支持的。不幸的是，它并没有完全处理层次结构，但JSON.Net在遇到时会回到JObject以支持它们。为了您的目的，它可能更直接。

以下是您提供的代码段和定义的示例。另请注意，ExpandoObject可直接转换为IDictionary<string, object>，而JObject则具有访问属性的显式方法。

人对应ExpandoObject，而JPerson对应JObject。

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

using System.Dynamic;

using Newtonsoft.Json;
using Newtonsoft.Json.Converters;
using Newtonsoft.Json.Linq;

namespace YourFavoriteNamespace
{
    public class JPerson
    {
        public string FNAME;
        public string LNAME;
        public BodyType bodyType;
        public JObject belongings;
        public JObject signs;
    }

    public class Person
    {
        public string FNAME;
        public string LNAME;
        public BodyType bodyType;
        public ExpandoObject belongings;
        public ExpandoObject signs;
    }

    public class BodyType
    {
        public int height;
        public int weight;
        public string race;
        public string hair;
    }

    class Program
    {
        static void DumpDynamic(dynamic d)
        {
            IDictionary<string, object> dynMap = (IDictionary<string, object>)d;
            foreach (string key in dynMap.Keys)
            {
                Console.WriteLine("  {0}={1} (type {2})", key, dynMap[key], null == dynMap[key] ? "null" : dynMap[key].GetType().Name);
            }
        }

        static void DumpJProperties(JObject jo)
        {
            var props = jo.Properties();
            foreach (JProperty prop in props)
            {
                Console.WriteLine("  {0}={1} (type {2})", prop.Name, prop.Value, null == prop.Value ? "null" : prop.Value.GetType().Name);
            }
        }

        static void DumpPerson(Person p)
        {
            Console.WriteLine("Person");
            Console.WriteLine("  FNAME={0}", p.FNAME);
            Console.WriteLine("  LNAME={0}", p.LNAME);
            Console.WriteLine("Person.BodyType");
            Console.WriteLine("  height={0}", p.bodyType.height);
            Console.WriteLine("  weight={0}", p.bodyType.weight);
            Console.WriteLine("  race  ={0}", p.bodyType.race);
            Console.WriteLine("  hair  ={0}", p.bodyType.hair);
            Console.WriteLine("Person.belongings");
            DumpDynamic(p.belongings);
            Console.WriteLine("Person.signs");
            DumpDynamic(p.signs);
        }

        static void DumpJPerson(JPerson p)
        {
            Console.WriteLine("Person");
            Console.WriteLine("  FNAME={0}", p.FNAME);
            Console.WriteLine("  LNAME={0}", p.LNAME);
            Console.WriteLine("Person.BodyType");
            Console.WriteLine("  height={0}", p.bodyType.height);
            Console.WriteLine("  weight={0}", p.bodyType.weight);
            Console.WriteLine("  race  ={0}", p.bodyType.race);
            Console.WriteLine("  hair  ={0}", p.bodyType.hair);
            Console.WriteLine("Person.belongings");
            DumpJProperties(p.belongings);
            Console.WriteLine("Person.signs");
            DumpJProperties(p.signs);
        }

        static void DoSimplePerson()
        {
            string initJson = "{\"FNAME\":\"joe\",\"LNAME\":\"doe\",\"BodyType\":{\"height\":180,\"weight\":\"200\",\"race\":\"white\",\"hair\":\"black\"},\"BELONGINGS\":{\"shirt\":\"black\",\"Money\":15,\"randomThing\":\"anyvar\"},\"Signs\":{\"tattoo\":0,\"scar\":\"forehead\",\"glasses\":\"dorky\"}}";
            Person p = JsonConvert.DeserializeObject<Person>(initJson);
            DumpPerson(p);
            Console.ReadLine();
        }

        static void DoComplexPerson()
        {
            string initJson = "{\"FNAME\":\"joe\",\"LNAME\":\"doe\",\"BodyType\":{\"height\":180,\"weight\":\"200\",\"race\":\"white\",\"hair\":\"black\"},\"BELONGINGS\":{\"shirt\":\"black\",\"Money\":15,\"randomThing\":\"anyvar\"},\"Signs\":{\"tattoo\":0,\"scar\":\"forehead\",\"glasses\":[\"dorky\",\"hipster\"]}}";
            Person p = JsonConvert.DeserializeObject<Person>(initJson);
            DumpPerson(p);
            Console.ReadLine();
        }

        static void DoJPerson()
        {
            string initJson = "{\"FNAME\":\"joe\",\"LNAME\":\"doe\",\"BodyType\":{\"height\":180,\"weight\":\"200\",\"race\":\"white\",\"hair\":\"black\"},\"BELONGINGS\":{\"shirt\":\"black\",\"Money\":15,\"randomThing\":\"anyvar\"},\"Signs\":{\"tattoo\":0,\"scar\":\"forehead\",\"glasses\":\"dorky\"}}";
            JPerson p = JsonConvert.DeserializeObject<JPerson>(initJson);
            DumpJPerson(p);
            Console.ReadLine();
        }

        static void Main(string[] args)
        {
            DoSimplePerson();
            DoComplexPerson();
            DoJPerson();
        }
    }
}

Answer 2

嗯，他们肯定是JSON对象，对，JSON对象是将字符串映射到某些东西的关联数组。所以我将它们表示为Dictionary<string, dynamic> - 一个字符串映射到某些东西。

使用动态变量解析JSON块

2 个答案: