Question

场景：在Amazon中搜索产品，然后按价格从低到高排序。
我想到的逻辑是-A）使用while页数浏览每页... B）将价格保存在列表中C）验证list [i]

如果您有更好的建议，请提出。

以下代码对我构成了哪些挑战：
1）页数不正确-实际计数应为5，这是我在页面上看到的内容，但程序会打印6
2）价格-该程序打印一些价格（我不知道它在打印什么）。当我尝试页面中的xpath时，它会四处移动，因此我认为它可以工作。
3）程序以异常结束

Exception in thread "main" org.openqa.selenium.WebDriverException: unknown error: Element <a href="/s?k=yellow+puma+shoes&amp;s=price-asc-rank&amp;lo=visual_grid&amp;page=4&amp;qid=1558648339&amp;ref=sr_pg_3">...</a> is not clickable at point (962, 579). Other element would receive the click: <div class="a-section aok-relative s-image-tall-aspect">...</div>

这是我的代码：

public class AmazonPriceTest {

    public static WebDriver driver;
    //public static List<WebElement> priceAsc;

    public static void main(String[] args) {
        System.setProperty("webdriver.chrome.driver", "C:\\Users\\Downloads\\chromedriver_win32\\chromedriver.exe");
        driver= new ChromeDriver();
        //WebDriverWait wait = new WebDriverWait(driver,30);
        driver.get("https://www.amazon.com/");

        driver.findElement(By.xpath("//input[@id='twotabsearchtextbox']")).sendKeys("yellow puma shoe");
        driver.findElement(By.xpath("//input[@value='Go']")).click();

        //Implicit wait till page loads
        driver.manage().timeouts().implicitlyWait(10,TimeUnit.SECONDS);

        //Click on result sort option where we will select price low to high
        Select sortBy=new Select(driver.findElement(By.xpath("//select[@name='s']")));
        sortBy.selectByValue("price-asc-rank");


        //Scroll down to find pagination
        JavascriptExecutor jse = (JavascriptExecutor) driver;
        jse.executeScript("window.scrollBy(0,5000)", "");
        //Number of Pages
        List<WebElement> pagesFound=driver.findElements(By.xpath("//ul[@class='a-pagination']//li//a[contains(@href, '/s?k=yellow+puma+shoes')]"));
        System.out.println("Pages found " + pagesFound.size());

        //Will click on Next link until we reach the last page and keep on saving price in list
        while(pagesFound.size()!=0){
            driver.findElement(By.xpath("//a[contains(text(),'Next')]")).click();
            List<WebElement> priceAsc=driver.findElements(By.xpath("//span[@class='a-offscreen']"));
            System.out.println(priceAsc.size());
        }

    }

}

如果您有空闲时间，我可以帮忙。在此先感谢您的时间。更新**：我进行了以下更改，现在它始终可以运行

try{
            while(pagesFound.size() >=0){
                driver.findElement(By.xpath("//a[contains(text(),'Next')]")).click();
                List<WebElement> priceAsc=driver.findElements(By.xpath("//span[@class='a-price']//span[@class='a-offscreen']"));
                //System.out.println(priceAsc.size());
                for(int i=0;i<priceAsc.size();i++){
                    System.out.println(priceAsc.get(i).getText());
                }
            }
        }
        catch (org.openqa.selenium.NoSuchElementException e)
        {
            System.exit(0);
        }
    }

}

按升序验证亚马逊价格-Java Selenium

0 个答案: