Question

这是我试图在这里If the "settlementDesc" in messages, has a string without ":" or " ", omit that entry of messages. If all entries are omitted in the messages, then remove the messages entry from the drug price response.达到的结果，因此在下面的代码中，它执行相反的操作，知道实现了什么错误吗？

main.js

const messages = [
              {
                "settlementCode": "99",
                "settlementDesc": "Not Covered: Call beneficios."
            },
               {
                "settlementCode": "85",
                "settlementDesc": ""
            },
              {
                "settlementCode": "65",
                "settlementDesc": ":"
            }
            ];

    function validateEntries (messages) {
      if(!messages){ return [] };
      const filteredMsg = messages.filter(mesg => {
        if (checkString(mesg)) return mesg
      } );

      return filteredMsg;
    };

    const checkString = (mesg) => {
      if (mesg.settlementDesc.indexOf(":") || mesg.settlementDesc.indexOf("")) {
        return false;
      } else {
        return true;
      }
    };


validateEntries(messages);

预期输出

[
              {
                "settlementCode": "99",
                "settlementDesc": "Not Covered: Call beneficios."
            }
            ]

Answer 1

不确定要什么，但是：

将字符串制成数组或对其进行过滤的一种方法是：

var myString = 'a b c';
console.log(myString.split(' '));

这将记录['a', 'b', 'c']的数组。

希望有帮助！

Answer 2

尝试使用include而不是indexOf，因为indexOf总是返回数字。

const messages = [
              {
                "settlementCode": "99",
                "settlementDesc": "Not Covered: Call beneficios."
            },
               {
                "settlementCode": "85",
                "settlementDesc": ""
            },
              {
                "settlementCode": "65",
                "settlementDesc": ":"
            }
            ];

    function validateEntries (messages) {
      if(!messages){ return [] };
      const filteredMsg = messages.filter(mesg => {
        if (checkString(mesg))  return mesg;
      } );

      return filteredMsg;
    };

    const checkString = (mesg) => {
      if (mesg.settlementDesc.includes(":")) {
        return true;
      } else {
        return false;
      }
    };


var output = validateEntries(messages);
console.log(output);

Answer 3

您可以过滤邮件列表并仅返回需要的邮件

 const messages = [
                  {
                    "settlementCode": "99",
                    "settlementDesc": "Not Covered: Call beneficios."
                },
                   {
                    "settlementCode": "85",
                    "settlementDesc": ""
                },
                  {
                    "settlementCode": "65",
                    "settlementDesc": ":"
                }
                ];

let filtered = messages.filter(item => item.settlementDesc.includes(":"))

如何检查字符串是否包含冒号或其空字符串？

3 个答案: