Question

单个数组中有多个值（一些值相似）怎么获得其中之一是获取值相似的数组最少重复1次，最多重复2次

例如此数组-

$array_value = array('ab','ab','cd','de','ab','cd','ab','de','xy');
foreach($array_value as $value){


}

我想要输出-ab，ab，cd，cd，de，xy

Answer 1

我认为您的输出shuold有两个 de 不是一个？

无论如何，这里是带有注释说明的代码：

<?php

$array_value = array('ab','ab','cd','de','ab','cd','ab','de','xy');

$arr_count = []; //we use this array to keep track of how many times we've added this
$new_arr = []; //we add elements to this array, or not.

foreach($array_value as $value){
    // we've added it before
    if (isset($arr_count[$value])) {
        // we only add it again one more time, no more.
        if ($arr_count[$value] < 2) {
            $arr_count[$value]++;
            $new_arr[] = $value;
        }
    }
    // we haven't added this before
    else {
        $arr_count[$value] = 1;
        $new_arr[] = $value;
    }
}

sort($new_arr); 

print_r($new_arr); 
/*
(
    [0] => ab
    [1] => ab
    [2] => cd
    [3] => cd
    [4] => de
    [5] => de
    [6] => xy
) */

PHP Demo

Answer 2

array_count_values返回数组中特定值的重复。因此，您可以使用它来简化代码并快速实现它。

$array_value = array('ab','ab','cd','de','ab','cd','ab','de','xy');
// Get count of every value in array
$array_count_values = array_count_values($array_value);
$result_array = array();
foreach ($array_count_values as $key => $value) {
    // Get $value as number of repetition of value and $key as value
    if($value > 2) {
        $value = 2;
        array_push($result_array, $key);
        array_push($result_array, $key);
    } else {
        for ($i=0; $i < $value; $i++) { 
            array_push($result_array, $key);
        }
    }
}
print_r($result_array);

多个数组值（某些值相同）如何仅获取两个值相同

2 个答案: