分段错误:使用pthread库的C中多线程程序中的11

时间:2019-05-23 09:00:57

标签: c pthreads

我需要使用pthread C库制作一个程序来处理线程。该任务的文本说:有一个走廊,该走廊有一个用于两个方向的单车道,并且有两种类型的员工将越过走廊到达走廊的另一侧。有类型1的员工从左到右,类型2的员工从右到左。在这条走廊中,有一个服务员在没人通过它时清洁它。清洁走廊时,双方的员工都等待走廊结束,否则,如果走廊被占用,员工表示无法清洁并入睡2秒钟。 当我编译该程序时,GCC编译器返回5警告,但没有错误。当我运行该程序时,立即出现分段错误:11。

这是更新的程序代码:

#include <stdio.h>
#include <stdlib.h>
#include <pthread.h>
#include <semaphore.h>
#include <unistd.h>


//global variables 
int c1,c2; //counters for imp1, imp2
pthread_mutex_t m1, m2;
sem_t corridor; 
double clean = 0.5;

//implementation thread attendant
void* attendant(void* arg){
    sleep(1); //rest 1 seconds
    if (c1==0 && c2==0){
        sem_wait(&corridor);
        printf("I'm starting to clean up\n");
        sleep(clean);
        printf ("I finished cleaning\n");
        sem_post(&corridor);
        }else{
           printf ("I can't clean, the corridor is busy\n");
        }
    return NULL;
}


//thread employee type 1
void* emp1(void *arg){
    printf("I'm the number %d of em1\n", c1);
    pthread_mutex_lock(&m1); //beginning critical section
    c1++;                    //it increases to signal the presence of a thread of the same type that wants to enter the corridor
    if (c1 == 1){            //the thread is the only one in the corridor. Can pass
        printf ("I am the first of my group emp1\n");
        sem_wait(&corridor);  //takes possession of the corridor
    }
    pthread_mutex_unlock(&m1); //allows other threads of the same type to pass in the corridor since it was the first in his group. End of critical section

    // invents "passage" function

    pthread_mutex_lock(&m1);  //beginning of the critical section. Once crossed the corridor, the variable c1 is modified. A mutex is used to avoid inconsistency
    c1--;
    if(c1 == 0){
        printf ("I am the last of my group emp1\n");
        sem_post(&corridor);
    } //if c1 == 0, it is the last thread imp1 and releases the corridor
    pthread_mutex_unlock(&m1); //end critical section
    return NULL;
}


//thread employee type 2 
void* emp2(void *arg){
    printf("I'm the number %d of emp2\n", c2);
    pthread_mutex_lock(&m2); //beginning critical section
    c2++;                    //it increases to signal the presence of a thread of the same type that wants to enter the corridor
    if (c2 == 1){            // the thread is the only one in the corridor. Can pass
        printf ("I am the first of my group emp2\n");
        sem_wait(&corridor);  //takes possession of the corridor
    }
    pthread_mutex_unlock(&m2); //allows other threads of the same type to pass in the corridor since it was the first in his group. End of critical sectionritica

    // invents "passage" function

    pthread_mutex_lock(&m2);  //beginning of the critical section. Once crossed the corridor, the variable c1 is modified. A mutex is used to avoid inconsistency
    c2--;
    if(c2 == 0){
        printf ("I am the last of my group emp2\n");
        sem_post(&corridor);
    }//if c1 == 0, it is the last thread imp1 and releases the corridor
    pthread_mutex_unlock(&m2); //end critical section
    return NULL;
}


int main(int argc, char const *argv[]) {
    //pthread_t emp1, emp2, attendant;
    pthread_t idt;
    int r; //var random to create thread emp1 or emp2
    int i; //index 

    //variable initialization
    c1 = c2 = 0;
    pthread_mutex_init(&m1, NULL); 
    pthread_mutex_init(&m2, NULL);
    sem_init(&corridor,0,1); 

    pthread_create(&idt,NULL,attendant,NULL); 
    while(i<40){
        sleep(1);
        r = rand()%2;
        if(r==0){
            printf("Employee creation 1\n");
            pthread_create(&idt,NULL,emp1,NULL);
        }else{
            printf("Employee creation 2\n");
            pthread_create(&idt,NULL,emp2,NULL);
        }
        i++;
    pthread_join(idt, NULL);
    }
    return 0;
}

1 个答案:

答案 0 :(得分:1)

pthread_t emp1, emp2, attendant;用相同的名称遮盖函数,因此pthread_create(&idt,NULL,attendant,NULL);将变量attendant的未初始化值传递给pthread_create作为函数指针而不是函数{{1 }}。

删除变量,根本就没有使用它们。

您还忘记了void* attendant(void* arg)

这将使您的程序编译:https://ideone.com/3CIb4J

此外,您的#include <unistd.h>函数不等待线程完成,您应该使用main等待线程。