我想从Edittext获取与给定的屏幕截图相同的文本(多行)。
我想从Edittext获得getText()时在下面的输出。
输出:
Lorem Ipsum只是假的
印刷文字和
排版行业。洛雷姆
Ipsum一直是行业
标准伪文本。
我已经尝试过以下解决方案,但它不起作用
etMessage.getText().toString().replaceAll("\\n", "<br />")
答案 0 :(得分:2)
经过过多搜索并等待对此问题的答案。我已经解决了这个问题。
解决方案: 我已经测量了每一行和每个单词,以将其保存为多行文本,您可以使用以下功能。
DisplayMetrics metrics = new DisplayMetrics();
getActivity().getWindowManager().getDefaultDisplay().getMetrics(metrics);
float density = metrics.density;
String result = fitString(ipText, ipText.getText().toString());
private String fitString(EditText editText, String message) {
Log.i(TAG, "fitString: Default String : " + message);
StringBuilder finalMessage = new StringBuilder();
if (isTooLarge(editText, message)) {
Log.i(TAG, "fitString: isTooLarge 1 : " + true);
List<String> lineList = Arrays.asList(message.split("\n"));
Log.i(TAG, "fitString: stringList" + lineList);
if (lineList != null && lineList.size() > 0) {
for (int i = 0; i < lineList.size(); i++) {
if (lineList.get(i) != null && !lineList.get(i).isEmpty()) {
if (isTooLarge(editText, lineList.get(i))) {
Log.i(TAG, "fitString: isTooLarge 2 : " + lineList.get(i) + " == " + true);
List<String> wordList = Arrays.asList(lineList.get(i).split(" "));
Log.i(TAG, "fitString: wordList" + wordList);
if (wordList != null && wordList.size() > 0) {
Log.i(TAG, "fitString: wordList : " + wordList.size());
StringBuilder temp = new StringBuilder();
String lastWord = "";
for (int j = 0; j < wordList.size(); j++) {
if (wordList.get(j) != null && !wordList.get(j).isEmpty()) {
if (isTooLarge(editText, wordList.get(j))) {
Log.i(TAG, "fitString: isTooLarge 3 : " + wordList.get(j) + " == " + true);
String newString = fitCharacter(editText, wordList.get(j));
Log.i(TAG, "fitString: fitCharacter == " + newString);
if (j == (wordList.size() - 1) && i == (lineList.size() - 1)) {
finalMessage.append(newString);
} else {
finalMessage.append(newString + "\n");
}
} else {
if (j == 0) {
lastWord = wordList.get(j);
} else {
lastWord = " " + wordList.get(j);
}
temp.append(lastWord);
Log.i(TAG, "fitString: temp : " + temp);
Log.i(TAG, "fitString: lastWord : " + lastWord);
if (isTooLarge(editText, temp.toString())) {
temp.setLength(0); // clear String Builder, new StringBuilder()
temp.append(lastWord);
if (j == (wordList.size() - 1) && i != (lineList.size() - 1)) {
Log.i(TAG, "fitString: ###### 1");
finalMessage.append("\n" + lastWord.trim() + "\n");
} else {
Log.i(TAG, "fitString: ###### 2");
finalMessage.append("\n" + lastWord.trim());
}
} else {
if (j == (wordList.size() - 1) && i != (lineList.size() - 1)) {
Log.i(TAG, "fitString: ###### 3");
finalMessage.append(lastWord + "\n");
} else {
Log.i(TAG, "fitString: ###### 4");
finalMessage.append(lastWord);
}
}
Log.i(TAG, "fitString: finalMessage : " + finalMessage);
}
} else {
Log.e(TAG, "fitString: Word is Null or Empty.");
finalMessage.append(" ");
}
}
} else {
Log.e(TAG, "fitString: wordList is Null or Empty.");
}
} else {
Log.i(TAG, "fitString: isTooLarge 2 : " + lineList.get(i) + " == " + false);
if (i == (lineList.size() - 1)) {
finalMessage.append(lineList.get(i));
} else {
finalMessage.append(lineList.get(i) + "\n");
}
}
} else {
Log.e(TAG, "fitString: Line is Null or Empty.");
finalMessage.append(lineList.get(i) + "\n");
}
}
} else {
Log.e(TAG, "fitString: stringList is Null or Empty.");
finalMessage.append("");
}
return finalMessage.toString();
} else {
Log.i(TAG, "fitString: isTooLarge : " + false);
return message;
}
}
public String fitCharacter(EditText editText, String message) {
Log.i(TAG, "fitCharacter2: Default Word : " + message);
StringBuilder finalWord = new StringBuilder();
int startIndex = 0;
int endIndex = 1;
for (; ; ) {
String tempSplitWord = message.substring(startIndex, endIndex);
Log.i(TAG, "fitCharacter2: startIndex : " + startIndex + " endIndex : " + endIndex + " tempSplitWord : " + tempSplitWord);
if (!isTooLarge(editText, tempSplitWord)) { // isTooLarge
if (endIndex < message.length()) {
endIndex = endIndex + 1;
Log.i(TAG, "IF fitCharacter2: endIndex < message.length() " + endIndex + " < " + message.length());
} else {
String result = finalWord.append(tempSplitWord).toString();
Log.i(TAG, "IF RETURN RESULT : " + result);
return result;
}
} else {
endIndex = endIndex - 1;
String splitWord = message.substring(startIndex, endIndex);
Log.i(TAG, "ELSE fitCharacter2: startIndex : " + startIndex + " endIndex : " + endIndex + " splitWord : " + splitWord);
boolean isTooLarge = isTooLarge(editText, splitWord);
if (!isTooLarge) {
finalWord.append(splitWord + "\n");
}
startIndex = endIndex;
endIndex = endIndex + 1;
Log.i(TAG, "ELSE fitCharacter2: startIndex : " + startIndex + " endIndex : " + endIndex);
}
}
}
private boolean isTooLarge(EditText editText, String newText) {
if (editText != null && editText.getPaint() != null) {
float textWidth = editText.getPaint().measureText(newText);
return (textWidth >= (editText.getMeasuredWidth() - (12 * density))); // editText.getMeasuredWidth();
} else {
return false;
}
}
答案 1 :(得分:0)
您尝试过这个
message = etMessage.getText().toString().replaceAll("\\n", "<br />")
查看
答案 2 :(得分:0)
默认情况下,Android中的所有EditText小部件都是多行的。您可以配置行数和字符类型。通过将输入类型设置为多行即可达到目的。
[Authorize(Roles = "Administrator")]
public IActionResult Get()
{
// ...
}
答案 3 :(得分:0)
对于下一个来者,我发现该任务过于复杂。这是Kotlin中使用Paint.breakText()
的不错的扩展代码。也就是说,它可能可以进一步简化...
fun EditText.getMultilineText(): String {
val maxWidth = (width - paddingLeft - paddingRight).toFloat()
val original = text.toString().trim()
val len = original.length
val multiline = mutableListOf<String>()
var p = 0
var count = -1
while (count != 0) {
count = paint.breakText(original, p, len, true, maxWidth, null)
if (p + count < len) {
var tmp = count
while (tmp > 0 && original[p + tmp - 1] != ' ') {
tmp -= 1
}
if (tmp > 0) {
count = tmp
}
}
val tmp = original.substring(p, p + count).trim()
if (tmp.isNotBlank()) {
multiline.add(tmp)
}
p += count
}
return multiline.joinToString("\r\n")
}