Question

我有文章和类别实体。该实体与映射无关，但是我需要使用查询生成器将Category链接到Article，结果我需要在Category实体中注入Article实体。我该怎么办？

我搜索了Google但没有找到解决方法

class ArticleRepository extends ServiceEntityRepository
{
    public function __construct(RegistryInterface $registry)
    {
        parent::__construct($registry, Article::class);
    }

    public function getAll()
    {
        $query = $this->createQueryBuilder('articles')
            ->select('articles, category')
            ->join(\App\Entity\Category::class, 'category', 'WITH', 'articles.categoryId = category.id')
            ->getQuery();

        echo '<pre>';
        print_r($query->getResult());
        exit;
    }
?>

// output

Array
(
    [0] => App\Entity\Article Object
        (
            [id:App\Entity\Article:private] => 1
            [name:App\Entity\Article:private] => title1
            [text:App\Entity\Article:private] => text1
            [categoryId:App\Entity\Article:private] => 1
            [categories:App\Entity\Article:private] => 
        )

    [1] => App\Entity\Category Object
        (
            [id:App\Entity\Category:private] => 1
            [name:App\Entity\Category:private] => first cat
        )

    [2] => App\Entity\Article Object
        (
            [id:App\Entity\Article:private] => 2
            [name:App\Entity\Article:private] => title2
            [text:App\Entity\Article:private] => text2
            [categoryId:App\Entity\Article:private] => 1
            [categories:App\Entity\Article:private] => 
        )

    [3] => App\Entity\Article Object
        (
            [id:App\Entity\Article:private] => 3
            [name:App\Entity\Article:private] => title3
            [text:App\Entity\Article:private] => text3
            [categoryId:App\Entity\Article:private] => 2
            [categories:App\Entity\Article:private] => 
        )

    [4] => App\Entity\Category Object
        (
            [id:App\Entity\Category:private] => 2
            [name:App\Entity\Category:private] => second cat
        )

)

Answer 1

尝试以下方式：

n = 10
pd.Series(range(1, n+1), dtype=str).str.zfill(3).radd('VAL')

0    VAL001
1    VAL002
2    VAL003
3    VAL004
4    VAL005
5    VAL006
6    VAL007
7    VAL008
8    VAL009
9    VAL010
dtype: object

代替

n=500

如何使用查询生成器在准则2中注入联接对象

1 个答案: