我正在研究宁静的服务和看法。 关于这一点,我使用mysql和休眠5。 我的数据表是两个,并且具有引用关系。 当我更新主键时,会出现问题。 当我添加一个新数据然后更新另一个表(它们具有引用关系)中的现有数据时,HHH000346:托管刷新期间发生错误。
我已经在Google上进行搜索,但是找不到答案。
这是我的Entity类。
@Entity
@Table(name = "users")
@EntityListeners(AuditingEntityListener.class)
public class User {
private long serial;
private String username;
private String password;
public User() {
}
public User(long serial, String username, String password) {
setSerial(serial);
setUsername(username);
setPassword(password);
}
@Column(name = "serial", nullable = false)
@GeneratedValue(strategy = GenerationType.AUTO)
public long getSerial() {
return serial;
}
public void setSerial(long serial) {
this.serial = serial;
}
@Id
public String getUsername() {
return username;
}
public void setUsername(String username) {
this.username = username;
}
@Column(name = "password", nullable = false)
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
@Override
public String toString() {
return "serial: " + this.serial + ", username: " + this.username + ", password: " + this.password;
}
}
Entity
@Table(name = "sites")
@EntityListeners(AuditingEntityListener.class)
@IdClass(Site.class)
public class Site implements Serializable{
@ManyToOne
@JoinColumn(name="username",foreignKey=@ForeignKey(name="username"))
private String username;
private String siteURL;
@Id
public String getUsername() {
return username;
}
public void setUsername(String username) {
this.username = username;
}
@Id
public String getSiteURL() {
return siteURL;
}
public void setSiteURL(String siteName) {
this.siteURL = siteName;
}
}
这是班上有问题。
public class UserController {
@Autowired
private UserRepository userRepository;
@Autowired
private SiteRepository siteRepository;
private CryptoUtil passwordEncoder = new CryptoUtil();
...
@PutMapping("/users/{username}")
public User updateUser(@PathVariable(value = "username") String username, @Valid @RequestBody User userDetails)
throws ResourceNotFoundException {
User user = userRepository.findById(username)
.orElseThrow(() -> new ResourceNotFoundException("User not found on :: " + username));
List<Site> sites = siteRepository.findByUsername(user.getUsername());
userDetails.setPassword(passwordEncoder.encryptSHA256(userDetails.getPassword()));
final User updateUser = userRepository.save(userDetails);
for (Site site : sites)
{
site.setUsername(userDetails.getUsername());
site = siteRepository.save(site);
}
userRepository.delete(user);
return updateUser;
}
....
}
The for-each statement occurs error.
PLEASE HELP ME
答案 0 :(得分:0)
您为什么这样做?
@ManyToOne
@JoinColumn(name="username",foreignKey=@ForeignKey(name="username"))
private String username;
应为:
@ManyToOne
@JoinColumn(name="username",foreignKey=@ForeignKey(name="username"))
private User user;
我还将建议您将主键用作外键。
而且一个实体中不能有多个@Id
。