将唯一选择值分配给唯一一个变量

时间:2019-05-22 09:24:30

标签: mysql lua

我要说明LUA和SQL语句。我已经尝试过了,可以显示SELECT或进行UPDATE INSERT ...,但是我不知道如何将唯一返回的select值分配给变量

mysql = require "luasql.mysql"

env  = mysql.mysql()
conn = env:connect('table','user','pass','server')
--print(env,conn)

cursor,errorString = conn:execute([[select id from agent where extension = '9072']])
--print(cursor,errorString)

row = cursor:fetch ({}, "a")

while row do
   print(string.format("%s", row.id))
   row = cursor:fetch (row, "a")
end

-- close everything
cursor:close()
conn:close()
env:close()

我希望这样的事情: 值= 33

1 个答案:

答案 0 :(得分:0)

我愿意

EX1