Question

我有这个代码。

 arfffile = []

inputed = raw_input("Enter Evaluation for name including file extension...")

reader = open(inputed, 'r')

verses = []

for line in reader:
    verses.append(line)

for line in verses:
    if line.split('@') == "@":
        verses.pop(line)


numclusters = int(raw_input("Enter the number of clusters"))

clusters = {}

for i in range(1,numclusters+1):
    clusters["cluster"+str(i)] = 0



print clusters
 # If verse belongs to a cluster, increment the cluster count by one in the dictionary value.
for verse in verses:
    for k in clusters:
        if k in verse:
            clusters[k] += 1
        else:
            print "not in"

print clusters

yeslist = []

for verse in verses:
    for k in clusters:
        if k not in yeslist:
            yeslist.append((k,0))
        elif k in yeslist:
            print "already in" + k


for verse in verses:
    for k in clusters:
        if k in verse and "Yes" in verse:
            yeslist.append(yeslist.index(k), +1)


    # iterate through dictionary and iterate through the lines
    # need to read in file line by line, 



    # if "yes" and cluster x increment cluster 
    # need to work out percentage of possitive verses in each cluster.

arff文件的一个例子是

@relation tester999.arff_clustered

@attribute Instance_number numeric
@attribute allah numeric
@attribute day numeric
@attribute lord numeric
@attribute people numeric
@attribute earth numeric
@attribute men numeric
@attribute truth numeric
@attribute verily numeric
@attribute chapter numeric
@attribute verse numeric
@attribute CLASS {Yes,No}
@attribute Cluster {cluster1,cluster2,cluster3}

@data
0,1,0,0,0,0,0,0,0,1,1,No,cluster3
1,1,0,0,0,0,0,0,0,1,2,No,cluster3
2,0,0,0,0,0,0,0,0,1,3,No,cluster3
3,0,1,0,0,0,1,0,0,1,4,No,cluster3
4,0,0,0,0,0,0,0,0,1,5,No,cluster3
5,0,0,0,0,0,0,0,0,1,6,No,cluster3
6,0,0,0,0,0,0,0,0,1,7,No,cluster3
7,0,0,0,0,0,0,0,0,2,1,No,cluster3
8,1,0,0,0,0,0,0,0,2,2,No,cluster3
9,0,0,0,0,0,0,0,0,2,3,No,cluster3
10,0,0,0,0,0,0,0,0,2,4,No,cluster3
11,0,0,1,0,0,0,0,0,2,5,No,cluster2

目前，程序读入数据行，例如

0,1,0,0,0,0,0,0,0,1,1,No,cluster3

我创建了一个字典，用于检测数据文件中有多少个集群。在此示例中，有3. cluster1 cluster2和cluster3。然后代码将每个簇附加为在字典“簇”中表示为字符串的键值然后我遍历所有经文并计算每一行以查看它属于哪个集群。

我的下一步是尝试为每个群集计算其中出现“是”的行的次数。所以说数据中每行的字符串中有10行“是”，代码应该能够计算出这个行的出现次数。

到目前为止，我所做的代码就在这里

for verse in verses:
        for k in clusters:
            if k in verse and "Yes" in verse:
                yeslist.append(yeslist.index(k), +1)

我基本上创建一个名为“yeslist”的元组列表，其值为[[cluster1,0]，（cluster2,3）]

因此，对于每一行（表示为字符串），检查其中是否存在“是”，如果检查它属于哪个群集，则将该元组值递增1。

我很难想到如何做到这一点的逻辑......任何人都可以帮忙吗？

感谢。

Answer 1

import collections

inputed = raw_input("Enter Evaluation for name including file extension...")

reader = open(inputed, 'r')

verses = [ line.strip() for line in reader.readlines() if line[0] != '@' ]

reader.close()

cluster_count = collections.defaultdict(int)
yes_count = collections.defaultdict(int)

verse_infos = [ (split_verse[-1],split_verse[-2]) for split_verse \
                 in verses.split(",") ]

for verse in verse_infos:
    cluster_count[verse[0]]+=1
    if verse[1] == 'yes':
        yes_count[verse[0]]+=1

你最终得到两个词典：

cluster_count : keys = cluster#, values = count
yes_count     : keys = cluster#, values = #yes

如果你真的想要一个元组列表：

yes_tuples = ( x for x in sorted(yes_count.iteritems()) )

如何在python中增加元组值并在循环中搜索字符串

1 个答案: