我正在尝试获取哈希函数的键的字符串长度,并且在我尝试使用strlen的位置上,我一直在GDB中收到此错误:
"_strlen_sse2 () at ../sysdeps/x86_64/multiarch/../strlen.S:79
79 ../sysdeps/x86_64/multiarch/../strlen.S: No such file or directory."
我尝试运行gdb,不允许使用字符串类,我知道我的程序无法通过此代码行。
int table::hashfunc(char key[])
{
int hash = 0;
int k = 1;
int key_size = strlen(key); //PROGRAM DOESN'T RUN PAST HERE
for(int i = 0; i < key_size; ++i)
{
hash = hash + (int)key[i];
hash = pow(hash, k);
}
int index = hash % SIZE;
return index;
}
//This is where I call the hash function from.
int table::add_name(char character[], char movie[], char choice)
{
int index = hashfunc(character);
我希望将key_size设置为密钥中的字符数,但是当我检查gdb中的strlen(key)时,我得到了:
(gdb) print strlen(key)
$1 = (size_t (*)(const char *)) 0x7ffff7156620 <__strlen_sse2>
这是我在读取char键的地方:
do
{
cout << "Please enter the name of the film you
would like to add to: " <<endl;
cin.get(temp_movie, temp_size);
cin.ignore(100, '\n');
cout << "Enter 'C' to add a character,
enter 'A' to add an actor: " <<endl;
cin >> choice;
cin.ignore(100, '\n');
choice = toupper(choice);
cout << "Enter the name of the character or
actor you would like to add: " <<endl;
cin.get(temp_name, temp_size);
cin.ignore(100, '\n');
if(choice == 'C')
character_table.add_name(temp_name,
temp_movie, choice);
else if(choice == 'A')
actor_table.add_name(temp_name,
temp_movie, choice);
else
cout << "That is an invalid choice.
please try again." <<endl;
}while(choice != 'A' && choice != 'C');
答案 0 :(得分:2)
strlen
documentation这样说:
返回给定字节字符串的长度,即 字符数组中第一个元素由指向的字符 延伸到且不包括第一个空字符。该行为是 如果指向的字符数组中没有空字符,则未定义 到str。
您的char key[]
可能缺少结尾的空字符\0
。