如何获取requesterPractitionerId和performerOrganizationId的唯一值。我需要在单个数组中探索requesterPractitionerId和performerOrganizationId的唯一值。
[
{
id: '1043120',
requesterPractitionerId: '1043119',
},
{
id: '1043081',
requesterPractitionerId: '1043080'
},
{
id: 'e1dceebe-c5ba-46a5-a63a-bff709896af4',
requesterPractitionerId: 'e0a844e4-6c8a-489a-8bd6-1d62267d311e',
performerOrganizationId: '05D0889009',
},
{
id: '2709842f-41e3-4193-8607-fc34d3d24ec1',
requesterPractitionerId: 'e0a844e4-6c8a-489a-8bd6-1d62267d311e',
performerOrganizationId: '05D0889009'
}
]
预期输出:
1043119
1043080
e0a844e4-6c8a-489a-8bd6-1d62267d311e
05D0889009
我是Java语言的新手,并为此奋斗了两个小时。任何帮助都将不胜感激。
答案 0 :(得分:1)
一种解决方案是使用Array.reduce()从所需的属性中生成新的Set。之后,您可以spread
将集合中的项目放入数组中。
const input = [{id:'1043120',requesterPractitionerId:'1043119'},{id:'1043081',requesterPractitionerId:'1043080'},{id:'e1dceebe-c5ba-46a5-a63a-bff709896af4',requesterPractitionerId:'e0a844e4-6c8a-489a-8bd6-1d62267d311e',performerOrganizationId:'05D0889009',},{id:'2709842f-41e3-4193-8607-fc34d3d24ec1',requesterPractitionerId:'e0a844e4-6c8a-489a-8bd6-1d62267d311e',performerOrganizationId:'05D0889009'}];
let res = input.reduce((acc, o) =>
{
if (o.hasOwnProperty("requesterPractitionerId"))
acc.add(o.requesterPractitionerId);
if (o.hasOwnProperty("performerOrganizationId"))
acc.add(o.performerOrganizationId);
return acc;
}, new Set())
console.log([...res]);
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答案 1 :(得分:0)
非常简单-Set
和map
,reduce
和filter
:
const arr = [{id:'1043120',requesterPractitionerId:'1043119',},{id:'1043081',requesterPractitionerId:'1043080'},{id:'e1dceebe-c5ba-46a5-a63a-bff709896af4',requesterPractitionerId:'e0a844e4-6c8a-489a-8bd6-1d62267d311e',performerOrganizationId:'05D0889009',},{id:'2709842f-41e3-4193-8607-fc34d3d24ec1',requesterPractitionerId:'e0a844e4-6c8a-489a-8bd6-1d62267d311e',performerOrganizationId:'05D0889009'}];
const res = [...new Set(arr.map(({ requesterPractitionerId, performerOrganizationId }) => [requesterPractitionerId, performerOrganizationId]).reduce((acc, curr) => acc.concat(curr)).filter(Boolean))];
console.log(res);
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