Question

我的解决方案中有两个项目。一个是Angular Core 2.2 Web应用程序，另一个是包含域模型和dbcontext的类库项目。我想将连接字符串传递给dbcontext，以便我可以使用代码优先方法创建数据库。这是我的连接字符串

class PlatoIngredienteController extends Controller
{
    /**
     * Display a listing of the resource.
     *
     * @return \Illuminate\Http\Response
     */
    public function index()
    {
      $platos = Plato::all();
      $ingredientes = Ingrediente::all();
      $platoingredientes = PlatoIngrediente::all();
      return view('platoingrediente/index', compact('platos','ingredientes','platoingredientes'));
    }

    /**
     * Show the form for creating a new resource.
     *
     * @return \Illuminate\Http\Response
     */
    public function create()
    {
        $platos = Plato::all();
        $ingredientes = Ingrediente::all();
        $platoingredientes = PlatoIngrediente::all();
        return view('platoingrediente/create', compact('platos','ingredientes','platoingredientes'));
    }

    /**
     * Store a newly created resource in storage.
     *
     * @param  \Illuminate\Http\Request  $request
     * @return \Illuminate\Http\Response
     */
    public function store(Request $request)
    {

      $validatedData = $request->validate([
          'cantidad' => 'required|max:50',
          'id_plato' => 'required|max:50'
      ]);

      $platoingrediente = PlatoIngrediente::create($validatedData);
      return redirect('/platoingrediente')->with('success','El Plato se guardó correctamente en la base de datos');
    }

    /**
     * Display the specified resource.
     *
     * @param  \App\PlatoIngrediente  $platoIngrediente
     * @return \Illuminate\Http\Response
     */
    public function show($id)
    {
        //
    }

    /**
     * Show the form for editing the specified resource.
     *
     * @param  \App\PlatoIngrediente  $platoIngrediente
     * @return \Illuminate\Http\Response
     */
    public function edit($id)
    {
        //
    }

    /**
     * Update the specified resource in storage.
     *
     * @param  \Illuminate\Http\Request  $request
     * @param  \App\PlatoIngrediente  $platoIngrediente
     * @return \Illuminate\Http\Response
     */
    public function update(Request $request, $id)
    {
        //
    }

    /**
     * Remove the specified resource from storage.
     *
     * @param  \App\PlatoIngrediente  $platoIngrediente
     * @return \Illuminate\Http\Response
     */
    public function destroy($id)
    {
        //
    }
}

这是ConfigureService方法中的代码

"ConnectionStrings": {
"DataConnection": "Server=.;Database=Test;Trusted_Connection=True;MultipleActiveResultSets=true;Integrated Security=True;"

}

这是我的DBContext

 public void ConfigureServices(IServiceCollection services)
    {
        services.AddDbContextPool<TestContext>(context => context.UseSqlServer(Configuration.GetConnectionString("DataConnection")));
        services.AddMvc().SetCompatibilityVersion(CompatibilityVersion.Version_2_2);
    }

我是编码优先方法和点网核心的新手。请指导我该怎么办！

Answer 1

由于您将连接字符串配置为服务，因此可以像这样简单地注入DbContext类的构造函数：

public class TestContext : DbContext 
  { 
  public TestContext(DbContextOptions<TestContext> options):base(options)
         {

         }
   }

Answer 2

您必须将IConfiguration接口作为参数，从Microsoft.Extensions.Configuration传递到Startup类的构造函数（将其命名为任何名称，例如，我将其命名为{{1 }}。

然后，替换此行

_configuration

与此：

services.AddDbContextPool<TestContext>(context => context.UseSqlServer(Configuration.GetConnectionString("DataConnection")));

在thar之后，将此构造函数添加到您的services.AddDbContext<TestContext>(options => options.UseSqlServer(_configuration.GetConnectionString("DataConnection")));类中：

TestContext

使用public TestContext(DbContextOptions<TestContext> options) : base(options) { }中为DBContextOptions设置的配置为TestContext类注入种子

如何将ConnectionString从appsettings.json文件传递到点网核心2.2中的类库项目

2 个答案: