Question

当我从列表2（

时，我正在尝试折叠

当前，如果我打开一个列表，它将保持打开状态，并且不会关闭其他已经打开的列表。

HTML：

<ul class="components">

<!-- LIST 1 -->
  <li>
    <a href="#homeSubmenu" data-toggle="collapse" aria-expanded="false" class="dropdown-toggle">
      Home
    </a>
    <ul class="collapse list-unstyled" id="list1">
      <li>
        <a href="#">Inicio 1</a>
       </li>
       <li>
         <a href="#">Inicio 2</a>
        </li>
        <li>
          <a href="#">Inicio 3</a>
        </li>
     </ul>
   </li>

<!-- LIST 2 -->
   <li>
    <a href="#homeSubmenu" data-toggle="collapse" aria-expanded="false" class="dropdown-toggle">
      Second home
    </a>
    <ul class="collapse list-unstyled" id="list2">
      <li>
        <a href="#">Inicio 1</a>
       </li>
       <li>
         <a href="#">Inicio 2</a>
        </li>
        <li>
          <a href="#">Inicio 3</a>
        </li>
     </ul>
   </li>

<!-- LIST 3 -->
   < li >
    <a href="#homeSubmenu" data-toggle="collapse" aria-expanded="false" class="dropdown-toggle">
      Another Home
    </a>
    <ul class="collapse list-unstyled" id="list3">
      <li>
        <a href="#">Inicio 1</a>
       </li>
       <li>
         <a href="#">Inicio 2</a>
        </li>
        <li>
          <a href="#">Inicio 3</a>
        </li>
     </ul>
   </li>
</ul>

JavaScript：

$(function() {
 $('.components li a').click(function(e) {
   e.preventDefault();
   var $this = $(this);
   $this.closest('ul').children('li').removeClass('active');
   $this.parent().addClass('active');
 });
});

结果是所有选定的

项目都将保留，并且列表不折叠。

Answer 1

$(function() {
  $('.components li a').click(function(e) {
    e.preventDefault();
    var $this = $(this);
    var mainList = $this.closest('ul');
    var subLists = mainList.children('li').children('ul');

    mainList.children('li').removeClass('active');
    subLists.addClass('collapse');

    $this.parent().addClass('active');
    var selectedSublist = $this.closest('li').children('ul')
    if (selectedSublist.hasClass('collapse'))
      selectedSublist.removeClass('collapse');
    else
      selectedSublist.addClass('collapse');
  });
});

<link href="https://stackpath.bootstrapcdn.com/bootstrap/4.3.1/css/bootstrap.min.css" rel="stylesheet" />
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="components">
  <!-- LIST 1 -->
  <li>
    <a href="#homeSubmenu" data-toggle="collapse" aria-expanded="false" class="dropdown-toggle">
      Home
    </a>

    <ul class="collapse list-unstyled" id="list1">
      <li>
        <a href="#">Inicio 1</a>
      </li>
      <li>
        <a href="#">Inicio 2</a>
      </li>
      <li>
        <a href="#">Inicio 3</a>
      </li>
    </ul>
  </li>

  <!-- LIST 2 -->
  <li>
    <a href="#homeSubmenu" data-toggle="collapse" aria-expanded="false" class="dropdown-toggle">
      Second home
    </a>
    <ul class="collapse list-unstyled" id="list2">
      <li>
        <a href="#">Inicio 1</a>
      </li>
      <li>
        <a href="#">Inicio 2</a>
      </li>
      <li>
        <a href="#">Inicio 3</a>
      </li>
    </ul>
  </li>

  <!-- LIST 3 -->
  <li>
    <a href="#homeSubmenu" data-toggle="collapse" aria-expanded="false" class="dropdown-toggle">
      Another Home
    </a>
    <ul class="collapse list-unstyled" id="list3">
      <li>
        <a href="#">Inicio 1</a>
      </li>
      <li>
        <a href="#">Inicio 2</a>
      </li>
      <li>
        <a href="#">Inicio 3</a>
      </li>
    </ul>
  </li>
</ul>

从列表2或列表3中选择<li>时，如何折叠列表1？

1 个答案: