Question

一个非常基本的问题，如果一个数字可被3/5 / both / none整除，则尝试输出，但是当它们不为真时将返回2条语句。我该如何解决？

我试图移动其他缩进的位置，第一次它不会输出不是3或5的倍数的数字，第二次它将输出两个答案。

while True:
    z = input("Please enter a number- to end the program enter z as -1 ")
    if z % 3 == 0 and z % 5 ==0:
        print("Your number is a multiple of 3 and 5")
    elif z % 3 == 0 and z % 5 != 0:
        print("Your number is a multiple of 3")
    elif  z % 3 != 0 and z % 5 ==0:
        print("Your number  is a multiple of 5")
    if z == -1:
        break
   else:
       print("Your number is not a multiple of 3 or 5")

即如果按预期输入Your number is not a multiple of 3 or 5，则输入67。但是，如果输入Your number is a multiple of 3 and 5到15，并且Your number is not a multiple of 3 or 5是意外输出。

Answer 1

如果您到目前为止已纳入所有评论建议，则会得到以下信息：

while True:
    z = input("Please enter a number- to end the program enter z as -1 ")
    # cast to int
    z = int(z)
    # break early
    if z == -1:
        break
    elif z % 3 == 0 and z % 5 == 0:
        print("Your number is a multiple of 3 and 5")
    elif z % 3 == 0:
        print("Your number is a multiple of 3")
    elif z % 5 == 0:
        print("Your number is a multiple of 5")
    else:
        print("Your number is not a multiple of 3 or 5")

Answer 2

通过启动新的if块，您将结束前面的elif链。

if z == -1:
    break
else:
    print("Your number is not a multiple of 3 or 5")

正如@Daniel Junglas的评论所说，您应该像这样构造它：

z = input("Please enter a number- to end the program enter z as -1 ")
if z == -1:
    break
elif (z % 3 == 0) and (z % 5 == 0):
    print("Your number is a multiple of 3 and 5")
elif (z % 3 == 0) and (z % 5 != 0):
    print("Your number is a multiple of 3")
elif (z % 3 != 0) and (z % 5 == 0):
    print("Your number  is a multiple of 5")
else:
    print("Your number is not a multiple of 3 or 5")

如何解决'else'输出超过1个结果

2 个答案: