Question

我试图理解Apple的Codeable函数来解析JSON。我正在youtube上跟随一个教程，这是代码：

.099

当我尝试构建时，我面临6种不同的错误： Error Image

当我从XCode应用建议的修复程序无法解决问题和视频时，此人可以构建这些错误，而没有任何错误。

谁能告诉我我哪里出了问题，或者苹果改变了您使用可编码的方式解析json的方式？

Answer 1

根据您的尝试，您的词根是一本有2个键的字典，您需要按timeSeriesFX5Min键

class VCName:UIViewController {
   override func viewDidLoad() {
     super.viewDidLoad() 

    let jsonUrlString = "https://www.alphavantage.co/query?function=FX_INTRADAY&from_symbol=EUR&to_symbol=USD&interval=5min&apikey=demo"

    let urlObj = URL(string: jsonUrlString)

    URLSession.shared.dataTask(with: urlObj!) {(data, response, error) in
     guard let data = data else { return }  
    do {
        let forex = try JSONDecoder().decode(Root.self, from: data)
        print(forex.timeSeriesFX5Min)
    } catch {

        print(error)
    }

    }.resume()
  }
}       


struct Root: Codable { 
    let timeSeriesFX5Min: [String:Forex]

    enum CodingKeys: String, CodingKey { 
        case timeSeriesFX5Min = "Time Series FX (5min)"
    }
}


// MARK: - TimeSeriesFX5Min
struct Forex: Codable {
    let the1Open, the2High, the3Low, the4Close: String

    enum CodingKeys: String, CodingKey {
        case the1Open = "1. open"
        case the2High = "2. high"
        case the3Low = "3. low"
        case the4Close = "4. close"
    }
}

无法解析可编码的JSON

1 个答案: