Question

我想设置文件系统存储位置中提供的文件的正确URL

views.py

 if request.method=='POST' and request.FILES.get('myfile', None):
    myfile=request.FILES['myfile']
    print(myfile.name.split('.'))
    image_name_banner = image_name +'-' + 'banner' + '.' +myfile.name.split('.')[-1]
    print(image_name_banner)
    myfile.name = image_name_banner
    fs=FileSystemStorage(location='media/events/images')
    print(fs)
    filename=fs.save(myfile.name,myfile)
    print(filename)
    print(fs.url)
    uploadedfileurl=fs.path(filename)
    u_banner=uploadedfileurl
    print(u_banner)

u_banner将默认URL打印为media / filename.jpg

Answer 1

def upload_example(request):
    if request.method == 'POST' and request.FILES['myfile']: 
        myfile = request.FILES['myfile']
        fs = FileSystemStorage(location='media/events/images/')
        filename = fs.save(myfile.name, myfile) 
        uploaded_file_url = fs.url(filename)  # file url
        return render(request, 'yourpagehere.html', { 
        'uploaded_file_url': uploaded_file_url 
    }) 
    return render(request, 'yourpagehere.html')

uploaded_file_url包含上载文件的网址

有关文件上传的更多信息，可以在docs

中找到

如何在FileSystemStorage（位置）中为上载的文件设置url

1 个答案: