Question

我设置了MySQL服务器，并试图使用Arduino和Ethernet shield从SQL服务器获取数据。问题是我无法从输出中删除未使用的文本。

我对php不太了解，所以我不能尝试太多事情。

    <html>
    <head>
    <title>Try Session JSON</title>
    </head>
    <body>
    <?php

        $dbusername = "root";  
        $dbpassword = ""; 
        $server = "localhost"; 
        $dbconnect = mysqli_connect($server, $dbusername, $dbpassword);
        $dbselect = mysqli_select_db($dbconnect, "test");
        $sql="SELECT full_name FROM test.eattandance WHERE id=1";
        $records=mysqli_query($dbconnect,$sql);
        $json_array=array();
        while($row=mysqli_fetch_assoc($records))
    {
        $json_array[]=$row;
    }
        /*echo '<pre>';
        print_r($json_array);
        echo '</pre>';*/
    echo json_encode($json_array);
    ?>
    </body>
    </html>

我希望tryjson.php的输出为A1，但实际输出为[{"full_name":"A1"}]。

Answer 1

这是您想要的吗？

   <html>
    <head>
    <title>Try Session JSON</title>
    </head>
    <body>
    <?php

        $dbusername = "root";  
        $dbpassword = ""; 
        $server = "localhost"; 
        $dbconnect = mysqli_connect($server, $dbusername, $dbpassword);
        $dbselect = mysqli_select_db($dbconnect, "test");
        $sql="SELECT full_name FROM test.eattandance WHERE id=1";
        $records=mysqli_query($dbconnect,$sql);
        $json_array=array();
        while($row=mysqli_fetch_assoc($records))
        {
            $json_array[]=$row;
            echo $row['full_name'];
        }
    ?>
    </body>
    </html>

如何使用PHP仅显示全名

1 个答案: