我正在使用Zapier从Facebook收集销售线索,然后将其发送到我的CRM。 我有一个连接到我的CRM的脚本,该脚本应该可以处理潜在客户。 对于脚本将触发的每一个新线索, 该脚本收集从Zapier传递的数据,并将其转换为XML并将其发送给我的客户端。
除一件事外,所有事物都起作用。 PHPMailer似乎会对zapier造成麻烦,因为每当启用email()函数时,Zapier都会给我一个错误。
FYI-当我转到脚本URL并手动设置GET参数时,此方法有效。 xml正在发送。但是,从zapier触发脚本时会出现问题。
Zapier错误: “我们无法顺利通过您的考试。 该应用返回“内部服务器错误”,没有更多详细信息。您所连接的应用程序的服务器似乎已关闭或当前出现问题。如果没有报告的问题,请检查应用程序的状态页或与支持人员联系。”
<?php
$firstName = isset($_GET['firstName']) ? $_GET['firstName'] : '';
$lastName = isset($_GET['lastName']) ? $_GET['lastName'] : '';
$fullName = isset($_GET['fullName']) ? $_GET['fullName'] : '';
$phone = isset($_GET['phone']) ? $_GET['phone'] : '';
$experience = isset($_GET['experience']) ? $_GET['experience'] : '';
$city = isset($_GET['city']) ? $_GET['city'] : '';
$email = isset($_GET['email']) ? $_GET['email'] : '';
$utm_source = isset($_GET['utm_source']) ? $_GET['utm_source'] : '';
$campaignId = isset($_GET['campaignId']) ? $_GET['campaignId'] : '';
$utm_medium = isset($_GET['utm_medium']) ? $_GET['utm_medium'] : '';
require 'vendor/autoload.php';
header('Content-Type: text/plain');
function createXML($data,$dataSource){
$dom = new DOMDocument('1.0', 'utf-8');
$cv = $dom->createElement("cv");
$candidate = $dom->createElement('candidate');
$source_type = $dom->createElement('source_type');
function recursive($dom, $parent, $key, $value) {
if(is_array($value)) {
$new_parent = $dom->createElement($key);
foreach($value as $k => $v){
recursive($dom, $new_parent, $k, $v);
}
$parent->appendChild($new_parent);
} else {
$field = $dom->createElement($key, htmlspecialchars($value));
$parent->appendChild($field);
}
}
foreach($dataSource as $key => $value){
// api need COLUMN without end of _<number>
if(preg_match('/COLUMN_([0-9]+)/', $key)) $key = 'COLUMN';
recursive($dom, $source_type, $key, $value);
}
foreach($data as $key => $value){
// api need COLUMN without end of _<number>
if(preg_match('/COLUMN_([0-9]+)/', $key)) $key = 'COLUMN';
recursive($dom, $candidate, $key, $value);
}
// $cv->appendChild($candidate)
$cv->appendChild($candidate);
$cv->appendChild($source_type);
$dom->appendChild($cv);
$node = $cv->appendChild($source_type);
$node->setAttribute('type','other');
$dom->formatOutput = true;
return $dom;
}
$data = array(
"first_name" => filter_var($firstName, FILTER_SANITIZE_STRING),
"last_name" => filter_var($lastName, FILTER_SANITIZE_STRING),
"mobile" => filter_var($phone, FILTER_SANITIZE_STRING),
'email' => '',
'id' => '',
);
$dataSource = array(
"source_title" => filter_var($utm_source, FILTER_SANITIZE_STRING),
"first_name" => '',
"last_name" => '',
"mobile" => '',
"email" => '',
"employee_number" => '',
"department" => '',
"email" => '',
);
//problematic function
function email(){
global $xmlData;
$mail = new PHPMailer(true);
$mail->isHTML(false);
$mail->isSMTP();
$mail->setFrom('XML@gmail.com', 'Yashir CV Lead');
$mail->addAddress("BinaryRx@gmail.com");
$mail->Subject = "Yashir CV Lead";
$mail->Body = $xmlData;
$today = date('d-m-Y H:i:s');
$mail->send();
echo "Report Sent - " . $today;
}
///////// IF I uncomment bellow,Zapier will give me the following error:
//We had trouble sending your test through.
//The app returned "Internal Server Error" with no further details.
//It looks like the server for your connected app is down or currently experiencing problems.
//Please check the app's status page or contact support if there are no reported issues.
//Uncomment bellow.
// email();
?>
我希望每位潜在客户发送一封包含XML的电子邮件。
答案 0 :(得分:0)
两个关键问题。首先,您使用的是SMTP,但尚未将Host
设置为邮件服务器-因此,除非是localhost
,否则它将无法正常工作?
您要让PHPMailer引发异常(通过将true
传递给构造函数),但是在对PHPMailer的调用周围没有try / catch块,因此任何错误都将导致未捕获的异常-这将给您确切的症状。试试这个:
function email()
{
global $xmlData;
$mail = new PHPMailer(true);
try {
$mail->isHTML(false);
$mail->isSMTP();
$mail->setFrom('XML@gmail.com', 'Yashir CV Lead');
$mail->addAddress("BinaryRx@gmail.com");
$mail->Subject = "Yashir CV Lead";
$mail->Body = $xmlData;
$today = date('d-m-Y H:i:s');
$mail->send();
echo "Report Sent - ".$today;
} catch (Exception $e) {
echo 'Sending failed'.$e->getMessage();
}
}
总体而言,最主要的是一次调试一件事-在开始尝试执行取决于其功能的事情之前,请检查email()
函数是否确实独立工作,因为否则您将不知道哪个代码的一部分失败了。
如果您使用的是PHP 7.0或更高版本,则可以使用null coalesce operator简化对参数的初始检查。您可以替换为:
$firstName = isset($_GET['firstName']) ? $_GET['firstName'] : '';
具有:
$firstName = $_GET['firstName'] ?? '';