Question

我的数据看起来像

04/07/16, 12:51 AM - User1: Hi
04/07/16, 8:19 PM - User2: Here’s a link for you
https://www.abcd.com/folder/1SyuIUCa10tM37lT0F8Y3D
04/07/16, 8:29 PM - User2: Thanks

使用下面的代码，我可以将每条消息分成每行

data = []
for line in open('/content/drive/My Drive/sample.txt'):
    items = line.rstrip('\r\n').split('\t')   # strip new-line characters and split on column delimiter
    items = [item.strip() for item in items]  # strip extra whitespace off data items
    data.append(items)

但是，我不想分割换行符所在的行然后是链接。例如，第3行和第4行是一条消息，但他们由于换行符而分裂。

。

有没有一种方法可以避免在换行符后接http时拆分？

Answer 1

可能可以对其进行优化，但是它可以工作：

data = []                                                                
prev = ''                                                                

with open('C:/Users/kavanaghal/python/sample.txt', 'r', encoding='utf-8') as f:            
    prev = f.readline().strip()                                          

    while True:                                                          
        nxt = f.readline().strip()                                       

        if 'http' in nxt:                                                
            data.append(prev + ": " + nxt)                               
            prev = f.readline()                                          
            continue                                                     

        data.append(prev)                                                
        prev = nxt                                                       

        if not nxt:                                                      
            break                                                        

print(data)                                                              


>> ['04/07/16, 12:51 AM - User1: Hi', 
    '04/07/16, 8:19 PM - User2: Here's a link for you: https://www.abcd.com/folder/1SyuIUCa10tM37lT0F8Y3D', 
    '04/07/16, 8:29 PM - User2: Thanks']

Answer 2

一种方法是将其附加到列表中的最后一个条目上：

import re
data = []
with open('sample.txt', 'r') as f: # use open so the file closes automatically
    for line in f.readlines():
        if len(data) >= 1 and re.match(r'https?://(?:[-\w.]|(?:%[\da-fA-F]{2}))+', line):
            data[len(data) - 1] += f" {line.strip()}"
        else:
            data.append(line.strip())
for x in data:
    print(x)

输出：

04/07/16, 12:51 AM - User1: Hi
04/07/16, 8:19 PM - User2: Here’s a link for you https://www.abcd.com/folder/1SyuIUCa10tM37lT0F8Y3D
04/07/16, 8:29 PM - User2: Thanks

为正则表达式提供信用：Regex to extract URLs...

Answer 3

您需要一次读取整个文件：

all_lines = []
for index, line in enumerate(split):
    next_index = index + 1
    if next_index < len(split) and "https" in split[next_index]:
        line += split[next_index]
        del split[next_index]
    all_lines.append(line)

Answer 4

事后操作

data = []
for line in open('/content/drive/My Drive/sample.txt'):
    items = [item.strip() for item in line.rstrip('\r\n').split('\t')]
### now it is different from your code ###############################
    if items[0].startswith('http'):
        data[-1].append(items[0])
    else:
        data.append(items)

您可能希望使用正则表达式或其他替代.startswith()来更好地控制匹配的内容，但这应该可以帮助您入门。

新行拆分的条件跳过

4 个答案: