Question

我正在创建游戏子手，我希望能够记录哪些字母是正确的，以及多少字母是不正确的，然后在以后使用它在屏幕上写消息并结束游戏。我该怎么做？

当前，correct_guesses和incorrect_guesses都是列表，并且每次有正确或不正确的猜测时，都应将猜测追加到其列表中。

import turtle
import string
import random
import time


words = ["gypsy"]


letter_width = 25
space_width = 15
incorrect_guesses = []
correct_guesses = []


def create_turtle():
    global tori
    tori = turtle.Turtle()
    tori.shape('classic')
    tori.pensize(5)
    tori.speed(.5)


def play_game():
    create_turtle()
    choose_word()
    draw_scaffold()
    draw_hints()
    draw_blanks()
    listen_for_keypress()


def report_incorrect_guess(letter):
    if letter not in incorrect_guesses:
        body_parts[len(incorrect_guesses)]()
        incorrect_guesses.append(letter)
        tori.penup()
        x = -270 + len(incorrect_guesses * letter_width)
        y = 200
        tori.goto(x, y)
        tori.color("black")
        tori.write(letter, font=("Times New Roman", 33, "normal"))


def report_correct_guess(letter):
    tori.penup()
    tori.color("black")
    for i in range(len(word)):
        if word[i] == letter:
            offset = i * (letter_width + space_width)
            tori.goto(-245 + offset, -242)
            tori.write(letter, font=("Times New Roman", 33, "normal"))


def listen_for_keypress():
    screen = turtle.Screen()
    for letter in string.ascii_lowercase:
        screen.onkeypress((lambda l: lambda: on_key_press(l))(letter), letter)
    screen.listen()
    screen.mainloop()


def choose_word():
    global word
    word = random.choice(words)
    len(word)


def end_game(message):
    tori.pensize(50)
    tori.color("red")
    tori.penup()
    tori.goto(-150, 0)
    tori.pendown()
    tori.write(message)
    time.sleep(3)
    exit(0)


def on_key_press(letter):
    if letter in word:
        report_correct_guess(letter)
        if correct_guesses == len(word):
            end_game("YOU WIN! :)")
    elif letter not in word:
        report_incorrect_guess(letter)
        if incorrect_guesses == 9:
            end_game("YOU LOSE! X_X")

现在，游戏运行良好，直到结束。正确猜出所有字母后，游戏就会继续进行，您可以猜出更多不正确的字母，但是Turtle只会覆盖正确的字母。绘制完所有身体部位后，游戏会继续进行，但是会显示一条错误消息，指出这两个部位（特别是所指的部位）都有问题。

def report_incorrect_guess(letter):
    if letter not in incorrect_guesses:
        body_parts[len(incorrect_guesses)]() <-----
        incorrect_guesses.append(letter)
        tori.penup()
        x = -270 + len(incorrect_guesses * letter_width)
        y = 200
        tori.goto(x, y)
        tori.color("black")
        tori.write(letter, font=("Times New Roman", 33, "normal"))

def on_key_press(letter):
    if letter in word:
        report_correct_guess(letter)
        if correct_guesses == len(word):
            end_game("YOU WIN! :)")
    elif letter not in word:
        report_incorrect_guess(letter) <------
        if incorrect_guesses == 9:
            end_game("YOU LOSE! X_X")

Answer 1

为防止游戏继续到某一点，可以在游戏结束时使用变量gameOver，让gameOver = true结束。在您的listen_for_keypress()函数中，您的第一个测试应为if !gameOver。这样，游戏只能在gameOver = false时运行。

def on_key_press(letter):
    if letter in word:
        report_correct_guess(letter)
        if correct_guesses == len(word):
            gameOver = true
            end_game("YOU WIN! :)")
    elif letter not in word:
        report_incorrect_guess(letter)
        if incorrect_guesses == 9:
            gameOver = true
            end_game("YOU LOSE! X_X")

def listen_for_keypress():
    if !gameOver :
        screen = turtle.Screen()
        for letter in string.ascii_lowercase:
            screen.onkeypress((lambda l: lambda: on_key_press(l))(letter), letter)
        screen.listen()
        screen.mainloop()

如何记录分数，以便以后在代码中使用

1 个答案: