我需要查找文件中的第10个数字,并定义数字是偶数还是奇数
我只记得如何读取文件,不知道下一步该怎么做
string linia;
fstream plik;
plik.open("przyklad.txt", ios::in);
if(plik.good() == true)
{
while(!plik.eof())
{
getline(plik, linia);
cout << linia << endl;
}
plik.close();
}
system("PAUSE");
return(0);
答案 0 :(得分:1)
由于每个人对此问题都持否定态度,所以我将继续回答。 我们不能确定OP是否正在从正确的来源中学习,并且,正如他所说,他不记得下一步要做什么,这意味着他实际上没有选择的余地。
带有一些解释性注释的工作代码如下:
#include <iostream>
#include <fstream>
using namespace std;
// Returns wether the number is odd
bool isOdd(const int num){
return num % 2 != 0;
}
int main(){
// Open the file in input mode
ifstream inputFile("data.txt");
int count(0); // Represents the current line number we are checking
string line; // Represents the characters contained in the line we are checking
// The loop goes over ever single line
while(getline(inputFile, line)){
//Increase the line count by 1
++count;
//If the line we are on is either 0 (not possible due to instant increment), 10, 20, 30, ...
if(count % 10 == 0){
//Get the number (not safe since it's not guaranteed to be a number, however it's beyond the scope of the question)
int number = stoi(line);
//Ternary statement can be replaced with a simple if/else
cout << "The number " << number << " is " << (isOdd(number) ? "odd" : "even") << '\n';
}
}
return 0;
}